Percent error=(experimentally determined boiling point-actual boiling point)
=(124.1 - 125.7) = 1.6 °C
Quantity Number of significant figures
0.070020 meter 5
10,800 meters 5
0.010 square meter 2
5.00 cubic meters 1
507 thumbtacks 3
(5.3 x 10⁴) + (1.3 x 10⁴) =6.6 x 10⁴
(7.2 x 10⁻⁴) ÷ (1.8 x 10³)=4 x 10⁻⁷
10⁴ x 10⁻³ x 10⁶=10⁷
(9.12 x 10⁻¹) - (4.7 x 10⁻²)=(9.12 x 10⁻²) - (4.7 x 10⁻²)
=(91.2-4.7) x 10⁻²
=85.5 x 10⁻²
Answer: pH = 2.68
Explanation: pH = - log[H3O^+] .
HCl reacts with water : HCl + H2O -> Cl^- + H3O^+
So [H3O^+] = c(HCl) = 0.0021 M
pH = - log(0.0021) = 2.68
Answer:
Explanation:
Step 1: Data given
The equilibrium constant, Kc, for the following reaction is 4.76 * 10^-4 at 431 K
The equilibrium concentration of Cl2(g) is 0.233 M
Step 2: The balanced equation
PCl5(g) ⇄ PCl3(g) + Cl2(g)
Step 3: The initial concentration
[PCl5]= Y M
[PCl] = 0M
[Cl2] = 0M
Step 4: Calculate the concentration at equilibrium
[PCl5] = Y + X M = Y - 0.233 M
[PCl]= XM = 0.233 M
[Cl2]= XM = 0.233 M
Step 5: Define Kc
Kc = [Cl2]* [PCl3] / [PCl5]
4.76 * 10^-4 = 0.233² / (Y -0.233)
0.000476 = 0.05429 / (Y - 0.233)
Y - 0.233 = 0.05429 / 0.000476
Y - 0.233 = 114.05 M
Y = 114.283 M = the initial concentration
The concentration of PCl5 at the equilibrium is 114.05 M
fourth period
The third period is similar to the second, except the 3s and 3p sublevels are being filled. Because the 3d sublevel does not fill until after the 4s sublevel, the fourth period contains 18 elements, due to the 10 additional electrons that can be accommodated by the 3d orbitals.
Aluminium fluoride is the name of the ionic compound