an alkyne with molecular formula c5h8 is treated with excess hbr, and two different products are obtained, each of which has mol
1 answer:
The addition of excess HBr to an alkyne of formula C5H8 yields the products 2,2-dibromopentane and 3,3-dibromopentane as shown in the image attached.
The reaction of HBr with C5H8 is an addition reaction. There are two isomeric alkynes that both have the molecular formula C5H8. These isomeric alkynes are; 1-pentyne and 2-pentyne.
The addition of excess HBr to these two isomeric alkynes yields the products 2,2-dibromopentane and 3,3-dibromopentane. Both of these isomeric alkynes have the formula C5H10Br2.
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The density of a material is the mass of the material per unit volume. Here the weight of the same metal is 44.40g, 40.58g and 38.35g having volume 4.8 mL, 4.7 mL and 4.2 mL respectively. Thus the density of the metal as per the given data are, = 9.25g/mL,
= 8.634g/mL and
= 9.130g/mL respectively.
The equation of the standard deviation is √{∑(x - )÷N}
Now the mean of the density is {(9.25 + 8.634 + 9.130)/3} = 9.004 g/mL.
The difference of the density of the 1st metal sample (9.25-9.004) = 0.246 g/mL. Squaring the value = 0.060.
The difference of the density of the 2nd metal sample (9.004-8.634) =0.37 g/mL. Squaring the value = 0.136.
The difference of the density of the 3rd metal sample (9.130-9.004) = 0.126 g/mL. Squaring the value 0.015.
The total value of the squared digits = (0.060 + 0.136 + 0.015) = 0.211. By dividing the digit by 3 we get, 0.070. The standard deviation will be . Thus the standard deviation of the density value is 0.265g/mL.