First let us calculate for the number of moles needed:
moles NaOH = 0.125 M * 0.500 L = 0.0625 mol
The molar mass of NaOH is 40 g/mol, hence the mass is:
mass NaOH = 0.0625 mol * 40 g/mol
<span>mass NaOH = 2.5 grams</span>
We will use this formula for first order:
㏑[A] = - Kt +Ao
when we have t (given)= 30 min = 30 x 60 = 1800 s (we here convert time from min to second.
then we assume that the initial concentration Ao = 1
and the concentration of A (final concentration = 0.25
So by substitution:
㏑(0.25) = - K * 1800 + ㏑(1)
1.39 = K * 1800
∴ K = 0.00077 s^-1 or 7.7 x 10^-4
C. Mouth. is the answer to your question.
Answer:
-2, -1, 0, +1, +2
Explanation:
The quantum numbers describe the quantum state of an electron in an atom. These numbers are symbolized as n, l, m, and s. There are rules for the combination of these numbers. The angular quantum number (ℓ) is related to the magnetic number (<em>m</em>): if ℓ is equal to a number a, thus <em>m</em> can be any integer number between - a and +a.
According to this rule:
If ℓ = 2, thus <em>m</em> can be have a value of an integer between -2 and +2 ⇒ -2, -1, 0, +1, +2
Answer : 37 drops are delivered per milliliter of the solution.
Explanation :
The problem gives us lot of extra information.
We want to find the number of drops delivered in 1 milliliter here.
We have been given that, one drop of the solution delivers 0.027 mL of solution.
Let us use this as a conversion factor, 
Let us find number of drops in 1 mL using this conversion factor.

Therefore we can say that 37 drops are delivered per milliliter of the solution.