an alkyne with molecular formula c5h8 is treated with excess hbr, and two different products are obtained, each of which has mol
1 answer:
The addition of excess HBr to an alkyne of formula C5H8 yields the products 2,2-dibromopentane and 3,3-dibromopentane as shown in the image attached.
The reaction of HBr with C5H8 is an addition reaction. There are two isomeric alkynes that both have the molecular formula C5H8. These isomeric alkynes are; 1-pentyne and 2-pentyne.
The addition of excess HBr to these two isomeric alkynes yields the products 2,2-dibromopentane and 3,3-dibromopentane. Both of these isomeric alkynes have the formula C5H10Br2.
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Explanation:
- When a bond is formed by transfer of electrons from one atom to another then it results in the formation of an ionic bond.
An ionic bond is generally formed by a metal and a non-metal.
For example, lithium is an alkali metal with atomic number 3 and its electronic distribution is 2, 1.
And, chlorine is a non-metal with atomic number 17 and its electronic distribution is 2, 8, 7.
So, in order to complete their octet lithium needs to lose an electron and chlorine needs to gain an electron.
Hence, both of then on chemically combining together results in the formation of an ionic compound that is, lithium chloride (LiCl).
An ionic compound is formed by LiCl because lithium has donated its valence electron to the chlorine atom.
- On the other hand, if a bond is formed by sharing of electrons between the two chemically combining atoms then it is known as a covalent bond.
For example, is a covalent compound as electrons are being shared by each oxygen atom.