an alkyne with molecular formula c5h8 is treated with excess hbr, and two different products are obtained, each of which has mol
1 answer:
The addition of excess HBr to an alkyne of formula C5H8 yields the products 2,2-dibromopentane and 3,3-dibromopentane as shown in the image attached.
The reaction of HBr with C5H8 is an addition reaction. There are two isomeric alkynes that both have the molecular formula C5H8. These isomeric alkynes are; 1-pentyne and 2-pentyne.
The addition of excess HBr to these two isomeric alkynes yields the products 2,2-dibromopentane and 3,3-dibromopentane. Both of these isomeric alkynes have the formula C5H10Br2.
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<h3>Answer:</h3>
16.7 g H₂O
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<u>Step 1: Define</u>
[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)
[Given] 1.85 mol NaOH
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol NaOH → 1 mol H₂O
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
16.6685 g H₂O ≈ 16.7 g H₂O
Answer is 0.289nm.
Explanation: The wt % of Fe and wt % of V is given for a Fe-V alloy.
wt % of Fe in Fe-V alloy = 85%
wt % of V in Fe-V alloy = 15%
We need to calculate edge length of the unit cell having bcc structure.
Using density formula,
For calculating edge length,
For calculating , we use the formula
Similarly for calculating , we use the formula
From the periodic table, masses of the two elements can be written
Specific density of both the elements are
Putting and
formula's in edge length formula, we get
By calculating, we get