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3 years ago

Round 5.03 to 1 decimal place

2 answers:

4 0

5.03 rounded to the tenth (one decimal) place is merely 5.0. Round using the hundredths place decimal. All numbers below 5 go down, all above go up.

balandron [24]3 years ago

3 0

5.03 rounded to 1 decimal place is 5.0

You might be interested in

What is 33.61111111 in fraction form

madreJ [45]

The correct answer is: " $\frac{33,611}{1,000}$ " .

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<u>Step-by-step explanation</u>:

Based on the assumption that the "1" repeats infinitely; in the given value:

" 33.61111111 ...." ;

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Note that the "611" ; after the decimal point; this goes to the "thousandths";

place (is "3 (three) digits long.").

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As such; we rewrite the number as:

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" $\frac{33.611}{1}$ " ;

and we multiply BOTH the "numerator" And the "denominator" by: "1000" :

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→ " $\frac{(33.611)*(1000)}{(1)*(1000)}$ " ;

to get:

→ " $\frac{33611}{1000}$ " ; → which cannot be reduced any further.

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The correct answer is: " $\frac{33,611}{1,000}$ " .

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Hope this is helpful to you!

Wishing you the best!

_______

7 0

3 years ago

Solve the inequality. T/4 > 7

Digiron [165]

Answer:

T>28

Step-by-step explanation:

Multiply 4 to both sides to get your variable alone.

3 0

3 years ago

Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts

shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0

3 years ago

2(x+1)+3x=37 *what is x??

irina1246 [14]

2(x+1)+3x=37

simplifythe left side:

2x +2 +3x = 37

Combine like terms:

5x +2 = 37

Subtract 2 from both sides:

5x = 35

Divide both sides by 5:

x = 7

5 0

3 years ago

Read 2 more answers

6.371 in lowest terms

kozerog [31]

Well you would have to round this 5 and above goes up. Since 1 is lower than 5 that would leave you at 6.37. 7 rounds up so that would change to 6.4. Lastly 4 would round down, So that would leave you with 6. Now 6 is the simplest form but if your looking for rounded to the nearest tenth the answer would be 6.4. If your looking for rounded to the nearest 100th place 6.37. But over all simplest form is 6.

5 0

3 years ago