Branliest offered

Mathematics

1 answer:

lozanna [386]3 years ago

3 0

A. 0, 7 is your answer

hope this helps

You might be interested in

(Click Here)!!!!!!!!!!!!! Stop Here Does Anyone Knows The Answer Click Here !!!!!Help Quick ! Length Perimeter Thanks

Assoli18 [71]

Perimeter of figure EFGH=10,because they say that figure ABCD is similar t
o figure EFGH.Side BC is twice bigger than side FG and by knowing that it means that the perimeter of figure EFGH is half of the perimeter of figure ABCD,which is 20/2 and that gives 10.I hope it helped.. :-)

4 0

3 years ago

What is: 2/3 - 1/6= ??

4vir4ik [10]

The answer to your question is 0.5 you need to get a common denomem

4 0

3 years ago

Read 2 more answers

Describe the slope of the line.

valentinak56 [21]

Answer: the slope is 0 if you are talking about what is the slope of 2,-3 and -2,-3 because that’s what is in the picture

Step-by-step explanation: slope is the y values over the x values

3 0

3 years ago

In the standard x,y plane, a circle has a radius 6 and center (7, 3). The circle intersects the x-axis at (a, 0) and (b, 0). Wha

arsen [322]

Answer: The required value of a+b is 14.

Step-by-step explanation: Given that in the standard xy plane, a circle has a radius 6 and center (7, 3).

The circle intersects the x-axis at (a, 0) and (b, 0).

We are to find the value of a+b.

We know that

the standard equation of a circle with center at (h, k) and radius r units is given by

$(x-h)^2+(y-k)^2=r^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

For the given circle, we have

(h, k) = (7, 3) and r = 6 units.

So, from equation (i), we get

$(x-7)^2+(y-3)^2=6^2\\\\\Rightarrow (x-7)^2+(y-3)^2=36~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Since the circle (ii) passes through the points (a, 0) and (b, 0), so let the point be denoted by (c, 0), then we have

$(c-7)^2+(0-3)^2=36\\\\\Rightarrow (c-7)^2+9=36\\\\\Rightarrow (c-7)^2=27\\\\\Rightarrow c-7=\pm3\sqrt3~~~~~~~~~~~~~~~~~~~~~~[\textup{Taking square root on both sides}]\\\\\Rightarrow c=7\pm3\sqrt3$