All categories

3 years ago

A cylinder has a diameter of 5 inches and is 8 inches tall. What is the volume of the cylinder to the nearest tenth?

Mathematics

1 answer:

Sveta_85 [38]3 years ago

8 0

Answer:

Volume = 157 cubic inches

Step-by-step explanation:

Diameter = 5 inches

r = 5/2 inches

h = 8 inches

$Volume=\pi r^{2}h\\=3.14*\frac{5*5}{2*2}*8\\\\=3.14*5*5*2= 157\\$

Formula: πr²h

substitute: 3.14*(5/2)*5/2*8

You might be interested in

Triangle P Q R is shown. Angle Q P R is a right angle. The length of Q P is 8 StartRoot 3 EndRoot and the length of P R is 8.

Vika [28.1K]

Answer: Length of side QR is 16 units.

Step-by-step explanation: Given that dimensions of PQR

QPR= 90degrees

6 0

1 year ago

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0

3 years ago

HELP ME pleaseeeee ill mark you as brainiest if I get two answers

sergiy2304 [10]

Question 9

Given the segment XY with the endpoints X and Y

Given that the ray NM is the segment bisector XY

NM divides the segment XY into two equal parts

XM = MY

given

XM = 3x+1

MY = 8x-24

so substituting XM = 3x+1 and MY = 8x-24 in the equation

XM = MY

3x+1 = 8x-24

8x-3x = 1+24

5x = 25

divide both sides by 5

5x/5 = 25/5

x = 5

so the value of x = 5

As the length of the segment XY is:

Length of segment XY = XM + MY

= 3x+1 + 8x-24

= 11x - 23

substituting x = 5

= 11(5) - 23

= 55 - 23

= 32

Therefore,

The length of the segment = 32 units

Question 10)

Given the segment XY with the endpoints X and Y

Given that the line n is the segment bisector XY

The line divides the segment XY into two equal parts at M

XM = MY

given

XM = 5x+8

MY = 9x+12

so substituting XM = 5x+8 and MY = 9x+12 in the equation

XM = MY

5x+8 = 9x+12

9x-5x = 8-12

4x = -4

divide both sides by 4

4x/4 = -4/4

x = -1

so the value of x = -1

As the length of the segment XY is:

Length of segment XY = XM + MY

= 5x+8 + 9x+12

= 14x + 20

substituting x = 1

= 14(-1) + 20

= -14+20

= 6

Therefore,

The length of the segment XY = 6 units

8 0

2 years ago

Help with this question thx

mario62 [17]

Answer:

3.5ft

Step-by-step explanation:

3 0

3 years ago

ANSWER NUMBER 11 PLZ AND ILL MARK YOU BRAINLIEST !!!

Yakvenalex [24]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers