All categories

3 years ago

Preciso de 6/5 de um metro de tecido, quantas camisas posso fazer com 42 metros?

Mathematics

1 answer:

Marysya12 [62]3 years ago

6 0

Answer:

shjsjaajba

osozozosnwnais0

You might be interested in

Part A

Volgvan

Answer:

Part A = C

Part B = 1/12

Step-by-step explanation:

Part A= this is because you need all the outcomes from the coin and from the dice joined together .

Part B= Because there is only one outcome that shows how you get a head on the coin and 6 on the dice.

4 0

3 years ago

Finish this question fast

umka21 [38]

Answer:

B. -3d + 47.25

Step-by-step explanation:

Each of them has $15.75

Each spent $d

Amount each still has = 15.75 - d

Therefore, total amount the 3 of them has = 3(15.75 - d) = 3*15.75 - 3*d

= 47.25 - 3d

Which is also am equivalent of -3d + 47.25

4 0

3 years ago

Which statements are true regarding the sides and angles<br> of the triangle? Select three options.

ss7ja [257]

Answer:

What are the options?

Step-by-step explanation:

3 0

3 years ago

A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo

katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the box $V=x^2z$

Volume of the box $=12 ft^3\\$

$Therefore, x^2z=12\\z=\frac{12}{x^2}$

The material for the base costs $\$0.17/ft^2$ , the material for the sides costs $\$0.10/ft^2$ , and the material for the top costs $\$0.13/ft^2$ .

Area of the base $=x^2$

Cost of the Base $=\$0.17x^2$

Area of the sides $=4xz$

Cost of the sides= $=\$0.10(4xz)$

Area of the Top $=x^2$

Cost of the Base $=\$0.13x^2$

Total Cost, $C(x,z) =0.17x^2+0.13x^2+0.10(4xz)$

Substituting $z=\frac{12}{x^2}$

$C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}$

To minimize C(x), we solve for the derivative and obtain its critical point

$C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2$

Recall: $z=\frac{12}{x^2}=\frac{12}{2^2}=3\\$

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0

3 years ago

Y = x^2+ 7x - 5 can be written in the form y = (x + a)^2+b

BARSIC [14]

Answer:

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = (x - h)² + k (h, k) are the coordinates of the vertex

Given y = x² + 7x - 5

To express in vertex form use the method of completing the square

add/subtract ( half the coefficient of the x- term )²

y = x² + 2( $\frac{7}{2}$ )x + $\frac{49}{4}$ - $\frac{49}{4}$ - 5

y = (x + $\frac{7}{2}$ )² - $\frac{49}{4}$ - $\frac{20}{4}$

y = (x + $\frac{7}{2}$ )² - $\frac{69}{4}$

Hence

a = $\frac{7}{2}$ and b = - $\frac{69}{4}$

8 0

3 years ago