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Rashid [163]
4 years ago
7

Isosceles trapezoid ABCD has legs AB and CD and base BC. If AB=5y - 10, BC=6y+2, and CD = 2y+8, find the value of Y.

Mathematics
1 answer:
pishuonlain [190]4 years ago
3 0

Hello from MrBillDoesMath!

Answer:

Choice C    (6)

Discussion:

Since it is an isosceles trapezoid the length of the two legs (i.e.  AB = 5y-10 and CD = 2y+8) are equal.  In other words,

5y - 10 = 2 y + 8

Subtract 2y from each side:

5y - 2y - 10 = 8

Now add 10 to each side

5y - 2y - 10 + 10 = 8 + 10 =>

3y + 0 = 18 =>

3y = 18 =>

y = 6


Regards,  

MrB


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Vanyuwa [196]

Answer:

(i) the other two sides are 6 and  6\sqrt{2}

(ii) the other two sides are   \frac{4}{3} and                                         \frac{8}{3}

Step-by-step explanation:

(i)  Sine: sin(θ) = Opposite ÷ Hypotenuse

    Cosine: cos(θ) = Adjacent  ÷ Hypotenuse

    Tangent: tan(θ) = Opposite ÷ Adjacent

Here adjacent side = 6

opposite side = d

angle = 45°

other angles are 90° and 45°

tan (45) = Opposite ÷ Adjacent

 1 = d ÷ 6

∴ d = 6 × 1 = 6

so opposite side = 6

Hypotenuse ² = opposite side ² + adjacent side²

                      =  6² + 6²

                      = 36 + 36

                       = 72

hypotenuse = \sqrt{72}

                     = 6\sqrt{2}

the other two sides are 6 and  6\sqrt{2}

(ii) here adjacent side = 4√3

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other angles are 90° and 60°

opposite side = d

tan ( 30) = opposite ÷ adjacent

 \frac{1}{\sqrt{3}} = d ÷ 4√3

\frac{1}{\sqrt{3}} = d × (\frac{\sqrt{3}}{4})

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therefore d = \frac{4}{3}

therefore opposite side = \frac{4}{3}

Hypotenuse ² = opposite side ² + adjacent side²

                        =( \frac{4}{3})² +( \frac{4}{\sqrt{3}})²

                        = \frac{64}{9}

therefore hypotenuse = \sqrt{\frac{64}{9}}

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the other two sides are   \frac{4}{3} and                                    \frac{8}{3}

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Answer:

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