Isosceles trapezoid ABCD has legs AB and CD and base BC. If AB=5y - 10, BC=6y+2, and CD = 2y+8, find the value of Y.
1 answer:
Hello from MrBillDoesMath!
Answer:
Choice C (6)
Discussion:
Since it is an isosceles trapezoid the length of the two legs (i.e. AB = 5y-10 and CD = 2y+8) are equal. In other words,
5y - 10 = 2 y + 8
Subtract 2y from each side:
5y - 2y - 10 = 8
Now add 10 to each side
5y - 2y - 10 + 10 = 8 + 10 =>
3y + 0 = 18 =>
3y = 18 =>
y = 6
Regards,
MrB
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