How can the graph be used to predict the output (y- value) associated with an input of 3 1/2
1 answer:
The method to estimate the y - value from a graph is discussed below.
We have a graph.
We have to estimate how can the graph be used to predict the output (y- value) associated with an input of x = =
= 3.5
A diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.
According to the Question -
Assume that you have a graph plotted for the straight line given by -
y = 2x + 5 ...(1)
(Refer to the figure attached)
The x values are plotted along the horizontal line and the y values are plotted along the vertical axis. You can see in the diagram that for x = or 3.5 the corresponding value for y is 6.8. You can repeat the same process for almost any value of x. Similarly, you can find out the value of y without using graph. For x = 5, using Eq (1), we get -
y = 2 x 5 + 5 = 15
Hence, using this way you can predict the y - value for any input.
To solve more questions on Graphs, visit the link below -
#SPJ1
You might be interested in
Answer:
Null Hypothesis, : p = 0.20
Alternate Hypothesis, : p > 0.20
Step-by-step explanation:
We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.
We have to use a 0.05 significance level to test the claim that more than 20% of users develop nausea.
<em>Let p = population proportion of users who develop nausea</em>
So, <u>Null Hypothesis,</u> : p = 0.20
<u>Alternate Hypothesis</u>, : p > 0.20
Here, <u><em>null hypothesis</em></u> states that 20% of users develop nausea.
And <u><em>alternate hypothesis</em></u> states that more than 20% of users develop nausea.
The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.
T.S. = ~ N(0,1)
where, = proportion of users who develop nausea in a sample of 241 subjects =
n = sample of subjects = 241
So, the above hypothesis would be appropriate to conduct the test.