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Aliun [14]
3 years ago
7

Write 4^3 – 6x + 2^5 + 3 in standard form please

Mathematics
2 answers:
lara31 [8.8K]3 years ago
8 0

Answer:

2^5 + 4^3 – 6x + 3

Step-by-step explanation:

Order the numbers by decreasing exponents. Start with the 2^5, since it has an exponent of 5. Next is the 4^3 since it has an exponent of 3. After that is -6x since it has an exponent of 1. 3 is last because it has an exponent of 1 and it has no variables attached.

If this answer is correct, please make me Brainliest!

denis-greek [22]3 years ago
5 0
4^3 - 6x + 2^5 + 3 in standard form is -6x + 99
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16
x
2
+
16
x
=
42
Step 2: Subtract 42 from both sides.
16
x
2
+
16
x
−
42
=
42
−
42
16
x
2
+
16
x
−
42
=
0
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16
x
2
+
16
x
+
−
42
=
0
Step 3: Use quadratic formula with a=16, b=16, c=-42.
x
=
−
b
±
b
2
−
4
a
c
2
a
x
=
−
(
16
)
±
(
16
)
2
−
4
(
16
)
(
−
42
)
2
(
16
)
x
=
−
16
±
2944
32
x
=
−
1
2
+
1
4
46
or
x
=
−
1
2
+
−
1
4
46
Answer:
x
=
−
1
2
+
1
4
46
or
x
=
−
1
2
+
−
1
4
46
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3 years ago
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