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Aliun [14]
3 years ago
7

Write 4^3 – 6x + 2^5 + 3 in standard form please

Mathematics
2 answers:
lara31 [8.8K]3 years ago
8 0

Answer:

2^5 + 4^3 – 6x + 3

Step-by-step explanation:

Order the numbers by decreasing exponents. Start with the 2^5, since it has an exponent of 5. Next is the 4^3 since it has an exponent of 3. After that is -6x since it has an exponent of 1. 3 is last because it has an exponent of 1 and it has no variables attached.

If this answer is correct, please make me Brainliest!

denis-greek [22]3 years ago
5 0
4^3 - 6x + 2^5 + 3 in standard form is -6x + 99
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wariber [46]

Answer:

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

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Step-by-step explanation:

From the question we are told that:

Sample size 1 n_1=15

Spacing 1 s_1=8

Mean 1 \=x_1=8.48

Standard deviation 1 \sigma_1=0.96 kPa

Sample size 2 n_2=16

Spacing 2 s_2=6

Mean 1 \=x_1=9.93

Standard deviation 1\sigma_1=1.02 kPa

Generally the hypothesis is mathematically given as

Null H_0:\mu_1-\mu_2

Alternative H_a:\mu_1\mu_2

Generally the equation for pooled estimate is mathematically given by

  S=\sqrt{\frac{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2}{n_1+n_2-2} }

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 S=0.9905

Generally the equation for test statistics is mathematically given by

 t=\frac{\=x_1+\=x_2}{S\sqrt{\frac{1}{n _1}+\frac{1}{n_2}}}

 t=\frac{\=8.48-9.93}{0.9905\sqrt{\frac{1}{15}+\frac{1}{15}}}

 t=-4.00091

Therefore From table

 P value=P(t_{15+15-2}=4.00091)

 P value=0.00041918

 P

Therefore

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject H_0\ at\ 5% level of significance

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