If f(X)= 7x +5/3 - x =6x +5/3
y= 6x +5/3
6x= y-5/3
f^-1(y)=x=(y-5/3)/6
So we can write
f(f^-1(y))= f((y-5/3)/6) = 6 (y-5/3)/6 +5/3= y-5/3+5/3= y
The same result can be obtained for f^-1(f(x))=x
If the function is f(x)= 7x +5/(3-x) then it is not invertible since it is not injective (pictures)
Answer:
The equation for the relationship is .
Step-by-step explanation:
Given that point is part of a direct relationship. That is:
(1)
Where is the proportionality constant.
If we know that and
, then the proportionality constant is:
Lastly, the equation for the relationship is .