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Naya [18.7K]
3 years ago
13

The two functions intersect at (30, 725). What does this mean in terms of the context?

Mathematics
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

Step-by-step explanation:

(x,y)

x = hours they worked

y = money saved

They each will haver saved $725 after working 30 hours.

I hope I've helped you.

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1. Identify the correct values of a , b and c using the following quadratic equation -5x² + 52x - 52 *
jasenka [17]

Answer:

1 a=-5 b=52 c=-52

it is the required answer

3 0
4 years ago
Nicole needs 1 and a third cups of flour to bake a batch of cookies. How many batches can she make with 10 cups of flour?
kirill115 [55]
Nicole can make 7 batches with 2/3 cups of flour left
4 0
3 years ago
Based on the information marked in the diagram, ∆XYZ and ∆RST must be congruent.
saveliy_v [14]
The answer is A true
7 0
3 years ago
State the domain and range of the graph of this relation.
saw5 [17]

Answer:

Domain is { x> -15}

Range is { y >5}

Step-by-step explanation:

The domain is the possible x values

x is greater than -15 (open circle)

Domain is { x ≥ -15}

The range is the possible y values

y is greater than  5 (open circle)

Range is { y >5}

8 0
3 years ago
The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas
iren [92.7K]

For the last part, you have to find where f'(t) attains its maximum over 0\le t\le8. We have

f'(t)=-6\sin3t+6\cos2t

so that

f''(t)=-18\cos3t-12\sin2t

with critical points at t such that

-18\cos3t-12\sin2t=0

3\cos3t+2\sin2t=0

3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0

\cos t(3\cos^2t-9\sin^2t+4\sin t)=0

\cos t(12\sin^2t-4\sin t-3)=0

So either

\cos t=0\implies t=\dfrac{(2n+1)\pi}2

or

12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi

where n is any integer. We get 8 solutions over the given interval with n=0,1,2 from the first set of solutions, n=0,1 from the set of solutions where \sin t=\dfrac{1+\sqrt{10}}6, and n=1 from the set of solutions where \sin t=\dfrac{1-\sqrt{10}}6. They are approximately

\dfrac\pi2\approx2

\dfrac{3\pi}2\approx5

\dfrac{5\pi}2\approx8

\sin^{-1}\dfrac{1+\sqrt{10}}6\approx1

2\pi+\sin^{-1}\dfrac{1+\sqrt{10}}6\approx7

2\pi+\sin^{-1}\dfrac{1-\sqrt{10}}6\approx6

4 0
3 years ago
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