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Aleonysh [2.5K]
4 years ago
9

When a person drinks alcohol, the rate of urination increases. This suggest that antidiuretic hormone (ADH) may be affected by a

lcohol consumption in some way> Which of the following best accounts for the increase in urination?
a. alcohol stimulates the release of ADH
b. alcohol inhibits the binding of ADH to receptors in the nephron
c. alcohol could inhibit ADH release or binding of ADH to receptors in the nephron
d. alcohol inhibits the release of ADH
Biology
2 answers:
iragen [17]4 years ago
5 0

Answer:

Option d. alcohol inhibits the release of ADH

Explanation:

Anti-diuretic hormone (ADH), is a hormone that tells our kidney how much water needs to be conserved and it also helps to regulate and balance the water level in our blood.

Alcohol prevents the production of anti-diuretic hormone (ADH), which causes an increase in urine production and most times dehydration follows. Since the alcohol opposes the production of ADH, whenever we take in alcohol, our kidney is forced to generate more urine compared to the ones we generate normally. As this continues, we find ourselves urinating often and dehydration will set in because the hormone (ADH) which would have regulate our water level has be stop by the alcohol.

Ulleksa [173]4 years ago
4 0

Answer:

d. alcohol inhibits the release of ADH

Explanation:

Alcohol play an opposite role in water reabsorption. ADH is made in supraoptic nuclues of hypothalamus and transfers fby neuron to posterior pituatry where it gets stored and secreted. Alcohol stops the release of ADH from posterior pituatry which decreases the serum level of ADH. As the ADH level lowers it wont be able to reabsorb water from the distal/collecting tubules of kidneys leading to increase in urine volume and urination.

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Same is the case with male partner due to the probability that he would be the carrier is 1/2

If both are carrier then, there is only 1/4 chances that the offspring will have the disease (as per cross shown above).

Now, the probability that the offspring will have the disease = product of all the above probabilities. (The probability of occurrence of two independent events is equal to the product of their individual probabilities).

So, \frac{1}{2}x\frac{1}{2}x\frac{1}{4} = \frac{1}{16}

c) 1/8

The probability of female to be the carrier is 1/2

The probability male to be the carrier is 1/2

If both are carrier then, there is only 2/4 chances that the offspring will be the carrier of the disease (as per cross shown above).

Now, the probability that the offspring will be the carrier = product of all the above probabilities. (The probability of occurrence of two independent events is equal to the product of their individual probabilities).

\frac{1}{2}x\frac{1}{2}x\frac{2}{4} = \frac{1}{8}

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