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qaws [65]
3 years ago
13

Plot the points (2,0) and (2,-5) on the coordinate plane below.

Mathematics
1 answer:
Bess [88]3 years ago
8 0

Answer:

5 units

Step-by-step explanation:

Notice that the x-coordinate is the same for both points, but that the y-coordinates differ by five units.  The distance between these two points is therefore 5 units.

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Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the constant 'k' in the factored form?
fomenos
1, when you factor you get 6x(x^2-1)+4(x^2-1)=(6x+4)(x-1)(x+1)
7 0
3 years ago
What would be the answer of 5(x-2)=30 in dustributive property
lisabon 2012 [21]

Answer:

x = 8

Step-by-step explanation:

5(x-2)=30

Distribute

5x- 10 = 30

Add 10 to each side

5x-10+10 = 30+10

5x= 40

Divide by 5

5x/5=40/5

x = 8

3 0
3 years ago
Read 2 more answers
Multiply 5 1/2 x 1 2/5​
Masja [62]

Answer:

The answer I got was 7 7/10

(sorry if wrong!)

5 0
3 years ago
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If tan ⁡x=12/5, and 0°
Charra [1.4K]

The value of sin(2x) is \frac{120}{169}

Explanation:

Given that tan x =\frac{12}{5}

The formula for sin(2x) is \sin (2 x)=2 \sin x \cos x

Since, \tan x=\frac{o p p}{a d j}

Also, it is given that tan x =\frac{12}{5}

Thus, opp=12 and adj=5

To find the hypotenuse, let us use the pythagoras theorem,

\begin{aligned}h y p &=\sqrt{12^{2}+5^{2}} \\&=\sqrt{144+25} \\&=\sqrt{169} \\&=13\end{aligned}

Now, we can find the value of sin x and cos x.

\sin x=\frac{\text { opp }}{h y p}=\frac{12}{13}

\cos x=\frac{a d j}{h y p}=\frac{5}{13}

Now, substituting these values in the formula for sin 2x, we get,

\begin{aligned}\sin (2 x) &=2 \sin x \cos x \\&=2\left(\frac{12}{13}\right)\left(\frac{5}{13}\right) \\&=\frac{120}{169}\end{aligned}

Thus, the value of sin(2x) is \frac{120}{169}

8 0
2 years ago
If anyone can help it would be greatly appreciated!
Natali5045456 [20]

Answer:

Second answer choice

Step-by-step explanation:

Since -10 is outside t you multiple every number inside the parenthesis by -10

6 0
3 years ago
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