The complete question in the attached figure
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
Answer:
-103
243
Step-by-step explanation:
(q•r)(5) = q(r(5))
r(5) = 2(5²) + 1 = 51
q(51) = -2(51) - 1 = -103
(r•q)(5) = r(q(5))
q(5) = -2(5) - 1 = -11
r(-11) = 2(-11)² + 1 = 243
Answer:I am pretty sure it is the angels because the square can be a right and the roofs can be acute.
Step-by-step explanation:
Right angle is 90 degrees
Acute is less than 90 degrees
Obtuse is more than 90
Answer:
11x^3−2x^2+3x+11 this is the correct answer
<em>60%</em>
- <em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>5 ........... 100%</em>
<em>3 .................x%</em>
<em>x = 3×100/5</em>
<em>= 300/5</em>
<em>= 60%</em>
<em>Good luck ! </em>