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777dan777 [17]
3 years ago
8

Multiply 5 1/2 x 1 2/5​

Mathematics
2 answers:
Masja [62]3 years ago
5 0

Answer:

The answer I got was 7 7/10

(sorry if wrong!)

wariber [46]3 years ago
5 0

Step-by-step explanation:

5 \frac{1}{2}  \times 1 \frac{2}{5}  \\  \\  \frac{11}{2}  \times  \frac{7}{5}  \\  \\  \frac{77}{10 }  = 7.7

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Consider the Triangle Sum Theorem in relation to a right triangle. What conjecture can you make about the two acute angles of a
Anon25 [30]
They must be complementary. these 2 angles MUST equal 90 degrees because there is a right angle that is 90 degrees in the triangle already and all triangles have an angle sum of 180 degrees. the answer is complementary
7 0
3 years ago
22) Find the measure of angle A to the nearest degree. Find the length of side b, to tenths.
mr Goodwill [35]

Answer:

m∠A = 31

b = 13.3

Step-by-step explanation:

5 0
3 years ago
Explain how to get that answer!!
ra1l [238]
We need to simplify \frac{ \sqrt{14x^3} }{ \sqrt{18x} }

First lets factor \sqrt{14x^3}

\sqrt{14x^3} = \sqrt{14}  \sqrt{x^3}
\sqrt{14} =  \sqrt{2} \sqrt{7} by applying the radical rule \sqrt[n]{ab} =  \sqrt[n]{a} \sqrt[n]{b}
\sqrt{x^3} = x^{3/2} By applying the radical rule \sqrt[n]{x^m} = x^{m/n}

So
\sqrt{14x^3} = \sqrt{14}  \sqrt{x^3} = \sqrt{2} \sqrt{7}x^{3/2}

Now let's factor \sqrt{18x}
By applying the radical rule \sqrt[n]{ab} =  \sqrt[n]{a}  \sqrt[n]{b},
\sqrt{18x} =  \sqrt{18} \sqrt{x}
\sqrt{18} =  \sqrt{2} * 3

So \sqrt{18x} = \sqrt{2}*3 \sqrt{x}

So  \frac{ \sqrt{14x^3} }{ \sqrt{18x} } = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}  }

We know that \sqrt[n]{x} = x^{1/n} so \sqrt{x} = x^{1/2}

We now have \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}

We know that \frac{x^a}{x^b} = x^{a-b}
So \frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x

We now got \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}


We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} =   \frac{ \sqrt{7}x }{3}


All in All, we get \frac{ \sqrt{14x^3} }{ \sqrt{18x} } =  \frac{ \sqrt{7}x }{3}

Hope this helps! :D


6 0
3 years ago
CAN ANYBODY FIGURE THIS OUT ​
eimsori [14]

Because you are told the two are similar, find the ratio of them.

Side AB = ft and side EF is 25 feet.

This means the larger rectangle is 5 times larger ( 25 /5 = 5).

Area is in square units, so square the ratio: 5^2 = 25

The area of the larger rectangle is 25 times the area of the smaller one.

Area = 35 x 25 = 875 ft^2

6 0
3 years ago
What is the area of the rectangle?
den301095 [7]

Answer:

50\ units^{2}

Step-by-step explanation:

Plot the figure to better understand the problem

see the attached figure

we know that

If the figure is a rectangle          

then

AB=CD \\AD=BC

The area of the rectangle is equal to

A=B*h

 where  

B is the base  

h is the height  

the base B is equal to the distance AB

the height h is equal to the distance AD  

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

A(-5,5)\\B(0,-5)

substitute the values

d=\sqrt{(-5-5)^{2}+(0+5)^{2}}\\d=\sqrt{(-10)^{2}+(5)^{2}}\\dAB=\sqrt{125}\ units

Step 2

Find the distance AD

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

A(-5,5)\\D(-1,7)

substitute the values

d=\sqrt{(7-5)^{2}+(-1+5)^{2}}\\d=\sqrt{(2)^{2}+(4)^{2}}\\dAD=\sqrt{20}\ units

Step 3

Find the area of the rectangle

A=AB*AD

we have

dAB=\sqrt{125}\ units\\dAD=\sqrt{20}\ units

substitute

A=\sqrt{125}*\sqrt{20}\\A=\sqrt{2,500}\\A=50\ units^{2}

7 0
4 years ago
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