Y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m
so
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
so
points (-2,3) and (3,0)
slope is (0-3)/(3-(-2))=-3/(3+2)=-3/5
a point is (3,0) Or (-2,3)
so it could be
y-0=-3/5(x-3) or y-3=-3/5(x-(-2)) which is equal to y-3=-3/5(x+2)
that's the answer
B is answer
Answer:
7/4
Step-by-step explanation:
<span>They are the values of 'x' that make the function zero.
If you graph the function, they are the values of 'x' where the graph
crosses the x-axis.</span>
Answer:
Calculate the determinant. Calculate the matrix of cofactors. Transpose the matrix of cofactors to obtain the adjugate matrix. Divide each entry of the adjugate matrix by the determinant to obtain the inverse.
