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3 years ago

Does anyone know the answer to this? I’m stumped

Mathematics

1 answer:

mel-nik [20]3 years ago

7 0

Answer:

The two parabolas that are narrower than the parabola below are, y = -3.5x^2 + 2 and y = 5x^2 + 3x - 1.

Step-by-step explanation:

Also there’s an app called Desmos that really helps me with problems like this. It’s what I used to solve this problem

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WHAT IS 15 - 10 5/8=?

ICE Princess25 [194]

Answer:

the answer is 4 3/8

Step-by-step explanation:

decimal: 4.375

fraction: 4 3/8

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2 years ago

The formula for the area of a triangle is

umka21 [38]

Answer:

b = (2A)/h

Step-by-step explanation:

With area formula for triangle: A = (1/2)*b*h

Solve for b

2*A = 2*(1/2)*b*h

2A = bh

2A / h = b

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3 years ago

Rosario is rolling a six-sided number cube. Rosario rolls the number cube twice. What is the probability that Rosario gets the n

Marat540 [252]

It's a conditional probability

P( getting a given number AND getting again the same number)

P(of getting any number) =1/6
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3 years ago

Read 2 more answers

Solve x2 + 2x = 4 for x by completing the square. x equals plus or minus square root of 5 plus 1 x equals plus or minus square r

steposvetlana [31]

Answer:

x equals plus or minus square root of 5 minus 1

Step-by-step explanation:

we have

$x^{2} +2x=4$

Divide by 2 the coefficient of the x-term

$2/2=1$

squared the number

$1^2=1$

Adds both sides

$x^{2} +2x+1=4+1$

$x^{2} +2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

take the square root both sides

$x+1=(+/-)\sqrt{5}$

$x=(+/-)\sqrt{5}-1$

therefore

x equals plus or minus square root of 5 minus 1

4 0

3 years ago

If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.

Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

$(10x - 11) = (8x - 20) + 43$

Solve for x

$10x - 11 = 8x - 20 + 43$

$10x - 11 = 8x + 23$

Subtract 8x from both sides

$10x - 11 - 8x = 8x + 23 - 8x$

$2x - 11 = 23$

Add 11 to both sides

$2x - 11 + 11 = 23 + 11$

$2x = 34$

Divide both sides by 2

$\frac{2x}{2} = \frac{34}{2}$

$x = 17$

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

3 0

3 years ago