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denpristay [2]
3 years ago
9

Does anyone know the answer to this? I’m stumped

Mathematics
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

The two parabolas that are narrower than the parabola below are, y = -3.5x^2 + 2 and y = 5x^2 + 3x - 1.

Step-by-step explanation:

Also there’s an app called Desmos that really helps me with problems like this. It’s what I used to solve this problem

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Yasmeen bought 16 pizzas for her grade level classes.
torisob [31]

Answer:

183.20

Step-by-step explanation:

9.95x16=159.20

159.20+24=183.20

4 0
3 years ago
i forgot how to find equivalent fractions. i know that the bottom would be times by 3 to get 18 but if you times 3 by 3 it would
tester [92]
Set up a proportion.  take 3/6 = 20/x
Cross multiply 3 * x = 6 * 20
Simplify  3x = 120
Divide by 3  x = 40
So the denominator of the bottom fraction is 40
6 0
3 years ago
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Log 64 = x. Find X<br> ⁴
ozzi

Answer:

3

Step-by-step explanation:

Rewrite the logarithmic notation to index notation.

4^x=64

Change 64 to index notation

ie 64 = 4^3

Since the base is the same(4) cancel them out

You remain with x = 3

6 0
3 years ago
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Drag each length to match it to an equivalent length. 2 yards 5 inches returned to choices list. 2 feet 8 inches4 yards9 feet2 y
Grace [21]

Answer:

2 yards 5 inches will be equivalent to 77 inches

Step-by-step explanation:

Given length -

2 yards 5 inches

One yard has 36 inches

Two yards will have 2*36 = 72 inches

Thus, 2 yards 5 inches will sum up to 72 inches + 5 inches = 77 inches

Hence,  2 yards 5 inches will be equivalent to 77 inches

6 0
3 years ago
Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

5 0
3 years ago
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