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denpristay [2]
3 years ago
9

Does anyone know the answer to this? I’m stumped

Mathematics
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

The two parabolas that are narrower than the parabola below are, y = -3.5x^2 + 2 and y = 5x^2 + 3x - 1.

Step-by-step explanation:

Also there’s an app called Desmos that really helps me with problems like this. It’s what I used to solve this problem

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An obtuse angle because an obtuse is an angle that is greater than 90 degrees but less than 180.
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Two-fifths of one less than a number is less than three-fifths of one more than that number. What numbers are in the solution se
yaroslaw [1]
2/5 * (n - 1) < 3/5 * (n + 1)
2/5 * n - 2/5 < 3/5 * n + 3/5
- 2/5 - 3/5 < 3/5 * n - 2/5 * n
- 5/5 < 1/5 * n
- 1 < 1/5 * n      /*5
- 5 < n
n > - 5

n = x

The correct result would be B) <span>x > - 5.</span>
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3 years ago
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If i is raised to the 11th power then it can not simplify to be
pickupchik [31]

Answer:15

Step-by-step explanation:

i dont care

4 0
3 years ago
Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distribut
defon

Answer:

0.8665 = 86.65% probability that the sample mean would be at least $39000

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125:

This means that n = 125, s = \frac{7320}{\sqrt{125}} = 654.72

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{654.72}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

0.8665 = 86.65% probability that the sample mean would be at least $39000

4 0
3 years ago
What value of x makes the equation shown true? Show or explain what you did to get your answer. 5x – 1 = 19
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5x-1=19
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then you do 5x=20
divide the 5x over to the 20 and your final answer is 4.
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