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3 years ago

Does anyone know the answer to this? I’m stumped

Mathematics

1 answer:

mel-nik [20]3 years ago

7 0

Answer:

The two parabolas that are narrower than the parabola below are, y = -3.5x^2 + 2 and y = 5x^2 + 3x - 1.

Step-by-step explanation:

Also there’s an app called Desmos that really helps me with problems like this. It’s what I used to solve this problem

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The figure is a parallelogram.one diagonal measures 28 units. Is the figure a rectangle? Explain

guajiro [1.7K]

Answer:

The parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.

Step-by-step explanation:

Given the parallelogram with sides 20 and 21 units with diagonal length 28 units.

we have to tell it is a rectangle or not.

The given parallelogram is rectangle if the angle at vertices are of 90° i.e the two triangle formed must be right angles i.e it must satisfy Pythagoras theorem

$28^{2}$ = $20^{2}$ + $21^{2}$

784=400+441=881

Not verified

∴ The sides of the parallelogram do not meet at right angles.

Hence, the parallelogram is not rectangle because the sides of the parallelogram do not meet at right angles.

Hope it helps

Mark as brainliest

5 0

3 years ago

What is the experimental probability for the lowest frequency?<br> 3/18<br> 4/18<br> 18/4<br> 18/3

elena55 [62]

Answer:

18/3

Step-by-step explanation:

Took the test

5 0

2 years ago

((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

3 years ago

A bag of dog food contains 42 cups of dog food. Your dog eats 2 1/3 cups of dog food each day. How many days does the bag of dog

leva [86]

Answer: you keep adding 2 and 1/3 to get your answer. 18 day so the dog food should last up to 18days hope this helps

Dont take my word not 100% sure

3 0

3 years ago

Solve for x : 6x+ 1/4 (4x+8)> 12

loris [4]

Answer:

x > 10/7 or x > 1 3/7

Step-by-step explanation:

First simplify the left side of the inequality.

6x+ 1/4 (4x+8)> 12

6x+x+2>12

7x+2>12 Next, using the property of inequality, subtract two from both sides.

7x>10 Now divide by 7 to solve for x.

x>10/7 or x> 1 3/7

6 0

3 years ago