Please explain thank you!

Mathematics

2 answers:

dybincka [34]2 years ago

4 0

Answer:

56%

Step-by-step explanation:

Percent literally means for each 100 ("cent" coming from the Latin word for 100). All percents can be represented as fractions with 100 in the denominator: 3%, for instance, can be written as 3/100, and 4% as 4/100 (or reduced as 1/25).

We can go the other way with fractions: 3/5 can be written as the fraction 60/100, which is 60%.

In this problem, Ainsley spends 28/50 of her allowance at the coffee shop, which can be written as 56/100, or 56%

Rus_ich [418]2 years ago

3 0

Answer:

56%

Step-by-step explanation:

To find a percentage, you need to take a ration of the value you want and the total. In this case, 28 is the value and 50 is the total, right? Then, to make it a s

proper percentage, you multiply by 100. As such:

$\frac{28}{50} \times 100 = \frac{14}{25} \times 100 = \\ = 14 \times 4 = 56$

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Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$