All categories

3 years ago

Please explain thank you!

Mathematics

2 answers:

dybincka [34]3 years ago

4 0

Answer:

56%

Step-by-step explanation:

Percent literally means for each 100 ("cent" coming from the Latin word for 100). All percents can be represented as fractions with 100 in the denominator: 3%, for instance, can be written as 3/100, and 4% as 4/100 (or reduced as 1/25).

We can go the other way with fractions: 3/5 can be written as the fraction 60/100, which is 60%.

In this problem, Ainsley spends 28/50 of her allowance at the coffee shop, which can be written as 56/100, or 56%

Rus_ich [418]3 years ago

3 0

Answer:

56%

Step-by-step explanation:

To find a percentage, you need to take a ration of the value you want and the total. In this case, 28 is the value and 50 is the total, right? Then, to make it a s

proper percentage, you multiply by 100. As such:

$\frac{28}{50} \times 100 = \frac{14}{25} \times 100 = \\ = 14 \times 4 = 56$

You might be interested in

What is differnce when there is parentheses around a number being squared?

Svetach [21]

When parentheses are around a number being squared, the output value will always be positive.

For example: -2² vs (-2)²
-2² means the negative of the square of two, or -4
(-2)² means the square of negative two, or 4

5 0

3 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

3 years ago

4.2 divided by 8.19 =

Damm [24]

Well, 4.2 divided by 8.19 = 0.51282051282 But if you switch it to 8.19 divided by 4.2 that would equal 1.95

Hope I helped!

- Debbie

3 0

4 years ago

Read 2 more answers

Can anyone Help I have 25 questions, 2hr 40mins remaining,

11Alexandr11 [23.1K]

Combining the like-terms, the result of the addition of polynomials f(x) and g(x) is given by:

$f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}$

<h3>How do we add polynomials?</h3>

We add polynomials combining the like-terms, that is, adding terms with the same exponent.

In this problem, the polynomials are:

$f(x) = 3x^{\frac{1}{2}} + 7x^{-\frac{1}{4}} + 8x^{-4}$

$g(x) = -\frac{7}{4}x^{\frac{1}{2}} + 12x^{-\frac{1}{4}} - 21x^3$

Combining the like terms, the addition is given by:

$f(x) + g(x) = \left(3 - \frac{7}{4}\right)x^{\frac{1}{2}} + (7 + 12)x^{-\frac{1}{4}} + 8x^{-4} + 21x^3$

$f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}$

More can be learned about addition of polynomials at brainly.com/question/9438778

#SPJ1

8 0

2 years ago

Please help me :)))))

svetoff [14.1K]

Part a)

Answer: 5*sqrt(2pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi

Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"

============================================================

Part b)

Answer: 3*sqrt(3pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi

Note: the same issue comes up as before in part a)

============================================================

Part c)

Answer: sqrt(19pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi

8 0

3 years ago

Read 2 more answers