Answer:
D.
Step-by-step explanation:
-2*-3=6 -2*5=-10. -2*1=-2
-2*8=-16. -2*-2=4. -2*3=-6
-2*2=-4. -2*1=-2. -2*-4=8
Answer:
15.62 units.
Step-by-step explanation:
To commence with, find for the vector.
Points = (7,-5) and (2,-5)
7 + 2
-5 + -5
12
-10
Vector = 12
-10
Magnitude = y² + x²
Points = (12,-10)
-10² + 12²
100 + 144
244
Square root of 244 is 15.62
Therefore, the distance between the points is 15.62 units.
Hope it helps.
Answer:
10x^7-5x^6+15x^3
Step-by-step explanation:
Distribute the 5x^3 to all the terms
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
