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Elodia [21]
2 years ago
10

Sarosh receives 8% commission on the final price of the clothing he sells. A customer bought a $45.00 coat that was marked 20% o

ff and a $95.00 suit that was marked 30% off. What would Sarosh's commission be on that customer's purchase?
Mathematics
2 answers:
Ray Of Light [21]2 years ago
8 0

Answer:

1) 20% of $45 is $9

$9 - $45 = $36 total cost of coat

2) 30% of $95 is $28.50

$28.50 - 95 = $66.50 total cost of suit

3) $36 + $66.50 = $102.50 sarosh earn

4) 102.50 * 0.08 = $ 8.20

final answer is $ 8.20


lesya [120]2 years ago
4 0
You must find the discounted price of both items:

20% of $45 is $9.  Subtract 9 from 45 to get $36 as the final price of the coat.

30% of $95 is $28.50.  Subtract 28.50 from 95 to get $66.50 as the final price of the suit.

To find the commission Sarosh earns, first add the final prices of the items together:
36+66.50= $102.50

Now take 8% of the total price:
0.08 x 102.50= $8.20

Sarosh earned $8.20 commission on the purchase.
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Let <em>X</em> = temperature increase.

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The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

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Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

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Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

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