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3 years ago

Highest common multiple of 8 and 14

1 answer:

7 0

There is no specified highest common multiple of two numbers, because a number has an infinite number of multiples extending out to infinity. So, if anything, the highest common multiple of 8 and 14 is infinity.

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PLEASE HELP ASAP!!!!!

KATRIN_1 [288]

Answer:

Figure 3 because if u look at the figure it alines with the question its asking you

3 0

2 years ago

Type the correct answer in the box. Use numerals instead of words.

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

A line that passes through the point (x,y), with a y-intercept of b and a slope of m, can be represented by the equation $y = mx + b$ .

If a line has the slope of -0.5, then m=-0.5 and the equation of the line is

$y=-0.5x+b$

This line passes throughthe point (10,1), then the coordinates of this point satisfy the equation of the line:

$1=-0.5\cdot 10+b\\ \\1=-5+b\\ \\b=1+5\\ \\b=6$

and the equation of the line is

$y=-0.5x+6$

Since b=6, the y-intercept of the line is 6.

7 0

3 years ago

Read 2 more answers

Write each number as a fraction or Mixed number.<br> (Please help! I'm trying to promote!)

aivan3 [116]

Answer:

0.7 repeating is 7/9

0.04 repeating is 4/99

4.45 repeating 4 4/11

2.19191919...... is 2 19/99

hope this helps

have a good day :)

Step-by-step explanation:

6 0

3 years ago

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

3 years ago

Which expression below gives the average rate of change of the function g(x) = -x2 - 4x on the interval 6 ≤ x ≤ 8 ?

Paha777 [63]

Answer: -18

<u>Explanation:</u>

Average rate of change is slope: $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ . Need to find the y-coordinates: