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3 years ago

Dan weighs 108 kg. How many pounds does he weigh? Round your answer to the nearest whole pound.

Mathematics

1 answer:

Zarrin [17]3 years ago

6 0

If my math is correct he weighs 238 pounds

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The scale of a map is 1 inch: 250 miles. City A is 378 miles from City B. To the nearest tenth, how far is its distance on the m

juin [17]

This is a proportion question. We can express this as an equation where the answer is x:

$\frac{1}{250}$ = $\frac{x}{378}$

From there, you can just cross-multiply and divide to get:

$\frac{1 * 378}{250}$

A tenth of 250 is 25, so this is roughly $\frac{375}{250}$ or $\frac{17}{10}$ , so it'll be approximately 1.7 inches on the map.

6 0

3 years ago

Read 2 more answers

"Time headway" in traffic flow is the elapsed time between the time that one car finishes passing a fixed point and the instant

marysya [2.9K]

Answer:

Detailed explanation of the answer is given in the attached files. Please have a look.

Step-by-step explanation:

8 0

3 years ago

Choose all of the transformations that would change a triangle into one that is similar, but not congruent. Which transformation

Vsevolod [243]

You didn't supply a list. The so-called rigid transformations of translation, rotation and reflection create congruent triangles.

Generally it's dilation by a factor about a point is preserves similarity but not congruency. Any transformation which includes such scalings but is otherwise rigid also preserves similarity but not congruency.

8 0

3 years ago

Write the equation of each line in slope intercept form (If possible please show work)

kow [346]

Answer:

y = -2/3x-9

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -2/3x+b

We have a point we can substitute into the line

-5 = -2/3(-6)+b

Subtract 4 from each side

-5-4 =4+b-4

-9 =b

y = -2/3x-9

7 0

3 years ago

Please solve this<br> (Rational numbers 8th grade)

pochemuha

Question # 1

Answer:

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}$

Step-by-step explanation:

Given the expression

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$

$=-\frac{2}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$ ∵ $\frac{-2}{3}\times \frac{3}{5}=-\frac{2}{5}$

$=-\frac{2}{5}+\frac{1}{4}$ ∵ $\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=\frac{1}{4}$

$\mathrm{Least\:Common\:Multiplier\:of\:}5,\:4:\quad 20$

$=-\frac{8}{20}+\frac{5}{20}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-8+5}{20}$

$\mathrm{Add/Subtract\:the\:numbers:}\:-8+5=-3$

$=\frac{-3}{20}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{3}{20}$

Therefore,

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}$

Question # 2

Answer:

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}$

Step-by-step explanation:

Given

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}$

$=-\frac{6}{35}-\frac{1}{6}\times \frac{3}{2}\times \frac{2}{5}\times \frac{1}{14}$ ∵ $\frac{2}{5}\times \frac{-3}{7}=-\frac{6}{35}$

$=-\frac{6}{35}-\frac{1}{140}$ ∵ $\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=\frac{1}{140}$

$\mathrm{Least\:Common\:Multiplier\:of\:}35,\:140:\quad 140$

$=-\frac{24}{140}-\frac{1}{140}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-24-1}{140}$

$\mathrm{Subtract\:the\:numbers:}\:-24-1=-25$

$=\frac{-25}{140}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{25}{140}$

$\mathrm{Cancel\:the\:common\:factor:}\:5$

$=-\frac{5}{28}$

Therefore,

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}$

4 0

3 years ago