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Serggg [28]
3 years ago
9

Which product is positive?

Mathematics
2 answers:
Alexandra [31]3 years ago
4 0
D, obviously. You welcome
Katena32 [7]3 years ago
3 0

Answer:

D is it

Step-by-step explanation:

bc there is an even number of negatives

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Maria bought seven boxes a week later half of all her boxes were destroyed in a fire there are only 22 boxes left with how many
OlgaM077 [116]

Answer:

Step-by-step explanation:

she started off with 44 boxes

8 0
3 years ago
Please help ASAP due soon pretty easy question just stuck
KATRIN_1 [288]

Answer:

x=4 z=117

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
How many solutions does the equation have?
Elina [12.6K]

9514 1404 393

Answer:

  1 solution

Step-by-step explanation:

The coefficients of d are different on the two sides of the equation (3d vs 6d), so the equation has one solution.

__

Dividing by 3 gives ...

  d +11 = 2(d +33)

  d + 11 = 2d + 66

Adding -d-66 to both sides gives ...

  -55 = d . . . . . . the one solution

4 0
3 years ago
A four pack of batteries cost 5.16 at this price what is the cost of
Genrish500 [490]

Answer:

1.29 for 1 pack

Step-by-step explanation:

5.16/4=1.29

7 0
3 years ago
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