The answer is 0.08.

The word "is" in mathematics is another word for "equal to".
The word "of" in mathematics is another word for multiplication.
Let's keep the answer as x.
0.008 = 1/10 * x
1/10x = 0.008
x = 0.08

8 0

3 years ago

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7. Which of the following has a certain

Sliva [168]

Answer:

Step-by-step explanation:

February has 28 days and on leap years 29. so there is an 11/12 chance that a month will have 29 days. a coin is 50/50. rain is 7/10. and a is irrational.

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20If%20%7D%20%5Cint_%7B%5Cfrac%7B-1%7D%7B%5C

Elodia [21]

We want to evaluate

$\displaystyle \int_{-\frac1{\sqrt2}}^{\frac1{\sqrt2}} \sqrt{\left(\frac{x-1}{x+1}\right)^2 + \left(\frac{x+1}{x-1}\right)^2 - 2} \, dx$

First we note that the integrand is even (replacing x with -x doesn't fundamentally alter the function being integrated), so this is equal to

$\displaystyle 2 \int_0^{\frac1{\sqrt2}} \sqrt{\left(\frac{x-1}{x+1}\right)^2 + \left(\frac{x+1}{x-1}\right)^2 - 2} \, dx$

The radicand reduces significantly to

$\displaystyle \left(\frac{x-1}{x+1}\right)^2 + \left(\frac{x+1}{x-1}\right)^2 - 2 = \frac{16x^2}{(1-x^2)^2}$

so that taking the square root, we simplify the integral to

$\displaystyle 8 \int_0^{\frac1{\sqrt2}} \frac x{1-x^2} \, dx$

which is trivially computed with a substitution of $y = 1 - x^2$ and $dy=-2x\,dx$ :

$\displaystyle -4 \int_1^{\frac12} \frac{dy}y = 4 \int_{\frac12}^1 \frac{dy}y = -4 \ln\left(\frac12\right) = \ln(2^4) = \boxed{\ln(16)}$

7 0

1 year ago