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meriva
3 years ago
6

(2x^2+4x+3) - (4x^2 -2x-3)

Mathematics
2 answers:
ankoles [38]3 years ago
7 0

Answer:

x^{2}+6x+6 is your answer

oksano4ka [1.4K]3 years ago
7 0

Answer:

-2x^{2} + 6x + 6

Step-by-step explanation:

2x^2 - 4x^2 = -2x^2

4x - (-2x) = 6x

3 - (-3) = 6

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A chemical company makes two brands of antifreeze. The first brand is 20% pure antifreeze, and the second brand is 70% pure anti
andre [41]

Answer:

First brand of antifreeze: 21 gallons

Second brand of antifreeze: 9 gallons

Step-by-step explanation:

Let's call A the amount of  first brand of antifreeze. 20% pure antifreeze

Let's call B the amount of second brand of antifreeze. 70% pure antifreeze

The resulting mixture should have 35% pure antifreeze, and 30 gallons.

Then we know that the total amount of mixture will be:

A + B = 30

Then the total amount of pure antifreeze in the mixture will be:

0.2A + 0.7B = 0.35 * 30

0.2A + 0.7B = 10.5

Then we have two equations and two unknowns so we solve the system of equations. Multiply the first equation by -0.7 and add it to the second equation:

-0.7A -0.7B = -0.7*30

-0.7A -0.7B = -21

-0.7A -0.7B = -21

               +

0.2A + 0.7B = 10.5

--------------------------------------

-0.5A = -10.5

A = \frac{-10.5}{-0.5}

A = 21\ gallons

We substitute the value of A into one of the two equations and solve for B.

21 + B = 30

B = 9\ gallons

3 0
3 years ago
Please help ill give brainiest
vaieri [72.5K]

Answer:

give it

Step-by-step explanation:

the answer is m=1/4

8 0
3 years ago
Read 2 more answers
Carl is filling flowerpots with soil. Each flowerpot is a cylinder with a radius of 7cm and a height of 10 cm. If Carl has 24,00
mr_godi [17]

Answer:

16 pots

Step-by-step explanation:

We first need to find out the amount of dirt that can be filled into a single flowerpot.

We use the formula to find the cylinder's volume.

πr^{2}* h

Height is equal to ten, Radius is equal to 7.

49π * 10

≈ 1539.38

25,000 divided by 1539.38

≈ 16.24

He can fill 16 pots fully.

5 0
3 years ago
In a random sample of 8 ​people, the mean commute time to work was 35.5 minutes and the standard deviation was 7.4 minutes. A 90
konstantin123 [22]

Answer:

Margin of Error = 5.4088 ;

Confidence interval = (30.1 ; 40.9)

Interval estimate are almost the same

Step-by-step explanation:

Given that :

Population standard deviation, σ = 9.3

Sample size, n = 8

Xbar = 35.5

Confidence level = 90%

The confidence interval:

Xbar ± Margin of error

Margin of Error = Zcritical * σ/sqrt(n)

Zcritical at 90% = 1.645

Margin of Error = 1.645 * 9.3/sqrt(8) = 5.4088

Confidence interval :

Xbar ± Margin of error

35.5 ± 5.4088

Lower boundary = (35.5 - 5.4088) = 30.0912 = 30.1

Upper boundary = (35.5 + 5.4088) = 40.9088 = 40.9

(30.1 ; 40.9)

T distribution =. (30.5 ; 40.5)

Normal distribution = (30.1, 40.9)

4 0
3 years ago
Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0
BartSMP [9]

The power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}

We can write g(x) as,

\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\

We know that, \frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n} if |x| < 1

and \frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n  if |\frac{x}{6}| < 1

\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\     if |x| < 1 and  if |\frac{x}{6}| < 1

\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n) if |x| < 1

Therefore, the power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0
2 years ago
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