How would I do this question using odd co
2 answers:
Consecutive odd numbres are 2 apart they numbers are x and x+2 square of first plus 3 times 2nd is 24 first is x 2nd is x+2 x²+3(x+2)=24 easy x²+3x+6=24 minus 24 both sides x²+3x-18=0 factor (x+6)(x-3)=0 set to ezr x+6=0 x=-6 false, this is even x-3=0 x=3 x+2=5 the numbers are 3 and 5 9+15=24, yah 3 and 5 are numbers
So your equation would be (x)squared + 3(x+2) = 24 simplify: xsq + 3x + 6 = 24 xsq + 3x - 18 = 0 if we broke this down into multiplication, one of the multiplying factors would have to equal zero since the whole now equals 0 so, (x+6)(x-3) = 0 so, x+6 = 0, or x-3 = 0 solve: x = -6, or 3 then just choose the odd one
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