Question

How would I do this question using odd co

Answer 1

Consecutive odd numbres are 2 apart
they numbers are x and x+2
square of first plus 3 times 2nd is 24
first is x
2nd is x+2

x²+3(x+2)=24
easy
x²+3x+6=24
minus 24 both sides
x²+3x-18=0
factor
(x+6)(x-3)=0
set to ezr
x+6=0
x=-6
false, this is even
x-3=0
x=3
x+2=5

the numbers are  3 and 5
9+15=24, yah



3 and 5 are numbers

Answer 2

So your equation would be (x)squared + 3(x+2) = 24
simplify:
xsq + 3x + 6 = 24
xsq + 3x - 18 = 0
if we broke this down into multiplication, one of the multiplying factors would have to equal zero since the whole now equals 0 so,
(x+6)(x-3) = 0
so, x+6 = 0, or x-3 = 0
solve:
x = -6, or 3

then  just choose the odd one