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3 years ago

This is the front half of my study guide please help me

Mathematics

1 answer:

Olegator [25]3 years ago

8 0

1. 624 students

If you multiply .24 (24%) by 2600, you'll find that the answer is 624.

2. 11% increase in protein

Divide 48 by 54 (48 ÷ 54), you'll notice the answer is around 0.88888. Next subtract 0.88888 by 1. The answer will be around 0.11111.

3. 44% sale

Divide 200 by 360 (200 ÷ 360). The answer will be around 0.5555555556. Next, subtract this number from 1. THIS answer is equal around 0.4444444.

4. 9 players were NOT eligible

Multiply 60 by 0.85 (85%). The answer to this is 51. Subtract 51 from the original number (60). The answer is 9.

5. 420 students plan to go to college

Multiply 1200 by 0.35 (35%). The answer to this is 420.

6. 20% don't have an Instagram account

To make this easier, we'll double to statistics (instead of 4 out of 5, it's 8 out of 10). 8 divided by 10 = 0.8. Subtract 0.8 from 1. Now, you have you're answer: 0.2 or 20%.

I hope this helps! Sorry if some were incorrect. :)

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3x-2x+4=2+x+2<br><br><br> Help I don’t get this. Shoot I’ll give you some points

andrew-mc [135]

Answer:

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$3x - 2x + 4 = 2 + x + 2 \\ x + 4 = 4 + x \\ x - x = 4 - 4 \\ 0 = 0$

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✏ Hence, proved.

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2 years ago

Read 2 more answers

Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation?

REY [17]

X ·2 = 12x - 15

2x = 12x - 15

2x + (-12x) = (12x - 15) + (-12x)

Result: x = 3/2

8 0

3 years ago

Read 2 more answers

In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist

Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

$np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96$

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

$\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408$

#Define Y:

Y~(11.04,5.7408)

$P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291$

Hence, the probability of 12 or fewer is 0.8291

b. The probability that 5 or more fish were caught.

#Using normal approximation:

$P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968$

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above $P(X\geq 5)=0.9968$ and a , $P(X\leq 12)$ =0.7291

$P(5\leq X\leq 120\approx P(4.5\leq Y\leq 12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259$

Hence, the probability of between 5 and 12 is 0.7259

4 0

3 years ago

Solve for all values of x for -2|x+9|-6=-24

DerKrebs [107]

-2(x+9)-6=-24
-2x-18-6=-24
2x=0
x=0

2(x+9)-6=-24
2x+18-6=-24
2x=-36
x=-18

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3 years ago

Square 20cmx20xm

Oxana [17]

Answer:

8,000

Step-by-step explanation:

3 0

3 years ago

This is the front half of my study guide please help me​

This is the front half of my study guide please help me