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anzhelika [568]
3 years ago
14

Helpp me plzzz!!

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0

Answer:

side angle side. Seems contrary

Step-by-step explanation:

Alja [10]3 years ago
3 0

Answer:

side angle side. Seems contrary

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A bracelet is now reduced to £420.
jek_recluse [69]

Answer:

546

Step-by-step explanation:

4 0
3 years ago
Thaddeus wants to cover an area around a pond with natural slate stone. If the cost of the slate is $6.50 per square foot, how m
igomit [66]

Answer:

Cost of slate path using π:   $980.18 (nearest cent)

Cost of slate path using π = 3.14:   $979.68

Step-by-step explanation:

<u>Formula</u>

Area of a circle = πr²  (where r is the radius)

First, calculate the area of the slate path by subtracting the area of the pond from the area of the larger circle.

Area of larger circle = π · 8² = 64π ft²

Area of pond (smaller circle) = π · 4² = 16π ft²

⇒ area of slate path = 64π - 16π = 48π ft²

If the cost of the slate is $6.50 per ft² then,

Cost of slate path using π:

⇒ 48π × $6.50 = $980.18 (nearest cent)

Cost of slate path using π = 3.14:

⇒ 48 × 3.14 × $6.50 = $979.68

8 0
2 years ago
3. Now combine any like terms. What is the simplified product?
Lesechka [4]

Answer:

Step-by-step explanation:

(x + 1) (x + 2)

x2 + 2x + x + 2

x2 + 3x + 2

4 0
4 years ago
A_____is a set of assumptions about how sample data are selected and about the population from which the sample data are selecte
Yakvenalex [24]

Answer: probability sampling

Step-by-step explanation:

Probability sampling is used as a sampling method in which the researcher chooses samples from a large population using a method which is based on the theory of probability. For an item to be qualify as a probability sample, that item must be selected using a random selection. An example is the selection of 2 girls from a group of 20 students where 12 are girls and 8 are boys.

6 0
4 years ago
Find ∂w/∂s and ∂w/∂t using the appropriate Chain Rule.
Vesnalui [34]

Answer:

<h3>The value of \frac{\partial w}{\partial s} is e^{3t}-18e^{2s+t}</h3><h3>The value of \frac{\partial w}{\partial t} is 3e^{3t}-9e^{2s+t}</h3><h3>The partial derivative at s=-5 and t=10 is \frac{\partial w}{\partial s} is e^{30}-18</h3><h3>The partial derivative at s=-5 and t=10 is \frac{\partial w}{\partial t}=3(e^{30}-3)</h3>

Step-by-step explanation:

Given that the Function point are w=y^3-9x^2y

x=e^s, y=e^t and s = -5, t = 10

<h3>To find \frac{\partial w}{\partial s} and \frac{\partial w}{\partial t}using the appropriate Chain Rule : </h3>

w=y^3-9x^2y  

Substitute the values of x and y in the above equation we get

w=(e^t)^3-9(e^s)^2(e^t)

w=e^{3t}-9e^{2s}.e^t

<h3>Now  partially differentiating w with respect to s by using chain rule we have </h3>

\frac{\partial w}{\partial ∂s}=e^{3t}-9(e^{2s}).2(e^t)

=e^{3t}-18e^{2s}.(e^t)

=e^{3t}-18e^{2s+t}

<h3>Therefore the value of \frac{\partial w}{\partial s} is e^{3t}-18e^{2s+t}</h3>

w=e^{3t}-9e^{2s}.e^t

<h3>Now  partially differentiating w with respect to t by using chain rule we have </h3>

\frac{\partial w}{\partial t}=e^{3t}.(3)-9e^{2s}(e^t).(1)

=3e^{3t}-9e^{2s+t}

<h3>Therefore the value of \frac{\partial w}{\partial t} is 3e^{3t}-9e^{2s+t}</h3>

Now put s-5 and t=10 to evaluate each partial derivative at the given values of s and t :

\frac{\partial w}{\partial s}=e^{3t}-18e^{2s+t}

=e^{3(10}-18e^{2(-5)+10}

=e^{30}-18e^{-10+10}

=e^{30}-18e^0

=e^{30}-18

<h3>Therefore the partial derivative at s=-5 and t=10 is \frac{\partial w}{\partial s} is e^{30}-18</h3>

\frac{\partial w}{\partial t}=3e^{3t}-9e^{2s+t}

=3e^{3(10)}-9e^{2(-5)+10}

=3e^{30}-9e{-10+10}

=3e^{30}-9e{0}

=3e^{30}-9

\frac{\partial w}{\partial t}=3(e^{30}-3)

<h3>Therefore the partial derivative at s=-5 and t=10 is \frac{\partial w}{\partial t}=3(e^{30}-3)</h3>
6 0
3 years ago
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