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Delicious77 [7]
4 years ago
5

Find the exact value of sin 225º without using a calculator

Mathematics
2 answers:
kirill [66]4 years ago
8 0

Step-by-step explanation:

\sin \: 225 \degree \:  \\  =  \sin \: (180 \degree + 45\degree) \\  =  -  \sin \: 45 \degree \\  =  -  \frac{1}{ \sqrt{2} }  \\  =  -  \frac{\sqrt{2}}{2}\\= -  \frac{1.4142}{2}\\=-0.7071 \\  \red{ \boxed{\therefore \:  \sin \: 225 \degree  =   - 0.7071}}

aivan3 [116]4 years ago
6 0

Answer:

-√2+√6/4

Step-by-step explanation:

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Answer:

m=3 is the slope

Step-by-step explanation:

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3 years ago
You are drawing two cards, without replacement, from a standard deck of 52 cards. What is the
Serga [27]

Answer:

Dear student,

Answer to your query is provided below

Probability of drawing a 2 at first is (4/52) = (1/13)

Probability of drawing a face card in second try without replacement = 12/51

Step-by-step explanation:

Total no. Of cards = 52

Total no. Of cards of 2 = 4

Prob. Of drawing 2 = 4/52

Total no. Of face card = 12

Total no.of cards left in deck = 51

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3 years ago
Triangle MNO is an equilateral triangle with sides measuring 16 StartRoot 3 EndRoot units. Triangle M N O is an equilateral tria
Lesechka [4]

Answer:

The correct option is second one i.e 24 units.

Therefore the height of the triangle is

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Step-by-step explanation:

Given:

An equilateral triangle has all sides equal.

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NM = MO = ON =16\sqrt{3}

NR is perpendicular bisector to MO such that

MR=RO=\dfrac{MO}{2}=\dfrac{16\sqrt{3}}{2}=8\sqrt{3} .NR ⊥ Bisector.

To Find:

Height of the triangle = NR = ?

Solution :

Now we have a right angled triangle NRM at ∠R =90°,

So by applying Pythagoras theorem we get

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

Substituting the values we get

(MN)^{2} = (MR)^{2}+(NR)^{2}\\\\(16\sqrt{3})^{2}=(8\sqrt{3})^{2}+(NR)^{2}\\\\(NR)^{2}=768-192=576\\Square\ rooting\ we\ get\\NR=\sqrt{576}=24\ units

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6 0
3 years ago
Read 2 more answers
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We know that volume of rectangular prism is length times width times height.

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\text{Volume of the solid part of the vase}=2000-440

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