2 years ago

5 Anita is using 36 cards to set up a card game. She wants to make

Mathematics

1 answer:

serious [3.7K]2 years ago

3 0

Answer:

box is there so I'll put the money in the post

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F(2)= -3 as a coordinate point?

kirza4 [7]

f(x) = y

f(2) = -3

Point = (x, y) = (2, -3)

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4 years ago

Use the equation machine to help you solve the addition equation. k=8 k=9 k=17 k=26

jarptica [38.1K]

.k= 8 Hope this helps

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3 years ago

Michelle ordered 200 t shirts to sell at the school carnival. She paid $2.80 per shirt, plus 5% of the total order for shipping.

kap26 [50]

Answer:

12.75 dollars

Step-by-step explanation:

5% = 2.94$

150% = 7$

2.80 + 5% + 150% = 12.75 for each t-shirt she sale

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4 years ago

An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equiva

Ira Lisetskai [31]

Answer:

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

$P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }$

we can plug back h

and we get

$P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }$

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

$0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }$

$0.80=(\frac{1}{2})^{\frac{t}{5730} }$

$\ln \left(0.8\right)=\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{5730}}\right)$

$t=-\frac{5730\ln \left(0.8\right)}{\ln \left(2\right)}$

$t=1844.6479$

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years

4 0

3 years ago

Read 2 more answers

Help me please. I have 2 attachments so you can see the graphs.

KIM [24]

Pretty sure that it is the first answer, the one with the back point between 6 & 8

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3 years ago