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frosja888 [35]
2 years ago
5

5 Anita is using 36 cards to set up a card game. She wants to make

Mathematics
1 answer:
serious [3.7K]2 years ago
3 0

Answer:

box is there so I'll put the money in the post

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What is the y-coordinate of the solution to this system of equations?<br> 5x-8y=1<br> 3x+6y=-21
Vanyuwa [196]

5x-8y=1...(1)
3x+6y=-21...(2)

(1)*3:
15x-24y=3...(3)

(2)*5:
15x+30y=-105...(2)

(3)-(2):
15x-24y-(15x+30y)=3-(-105)
15x-24y-15x-30y=108
-54y=108
y=-2
6 0
3 years ago
If m&lt;ECD is six less than five times m&lt;BCE. and m&lt;BCD = 162°, find each measure.(Sorry bout using the wrong signs, but
tia_tia [17]

Answer:

m∠BCE = 28° and m∠ECD = 134°

Step-by-step explanation:

* Lets explain how to solve the problem

- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD

- m∠ECD is six less than five times m∠BCE

- That means when we multiply measure of angle BCE by five and

 then subtract six from this product the answer will be the measure

 of angle ECD

∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)

∵ m∠BCD = m∠BCE + m∠ECD

∵ m∠BCD = 162°

∴ m∠BCE + m∠ECD = 162 ⇒ (2)

- Substitute equation (1) in equation (2) to replace angle ECD by

  angle BCE

∴ m∠BCE + (5 m∠BCE - 6) = 162

- Add the like terms

∴ 6 m∠BCE - 6 = 162

- Add 6 to both sides

∴ 6 m∠BCE = 168

- Divide both sides by 6

∴ m∠BCE = 28°

- Substitute the measure of angle BCE in equation (1) to find the

  measure of angle ECD

∵ m∠ECD = 5 m∠BCE - 6

∵ m∠BCE = 28°

∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°

* m∠BCE = 28° and m∠ECD = 134°

3 0
3 years ago
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Where does the graph of the linear equation, y = 1/2 x - 3, cross the y-axis?
makvit [3.9K]

negative 2 is where it crosses



4 0
3 years ago
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Help please i give thanks lol
maks197457 [2]
What is question . .
7 0
3 years ago
Explain how you got the answer please
kykrilka [37]
-2x + 12 = 2y

Add 2x on both sides,

12 = 2y + 2x

Divide by 2 on both sides,

6 = y + x -> x + y = 6

The answer is D.
4 0
3 years ago
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