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madam [21]
3 years ago
7

-2-|-5|+(-6)-(-2 ).

Mathematics
2 answers:
Elanso [62]3 years ago
3 0
I believe it is just a simple -7
atroni [7]3 years ago
3 0
-2 - |-5| + (-6) - (-2)
Take the absolute value of 5
-2 - 5 + (-6) - (-2)
Combine -2 and 5
-7 + (-6) - (-2)
Combine -6 and -2
-7 - 4 

And finally, the answer is 

-11
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Can anyone help with 20-22?
aliina [53]

Answer:

zx would equal 19 as well

wt=4.5

wy=19

Step-by-step explanation:

this is easy speacily since i am in 8th grade lol

3 0
3 years ago
One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fastt
mash [69]

Answer: 864\ m^2,\ 24\ m

Step-by-step explanation:

Given

Perimeter of the rhombus is 120\ m

Length of one of the diagonal is d_1=36\ m

All the sides of the rhombus are equal

\Rightarrow 4a=120\\\Rightarrow a=30\ m

Area of the rhombus with side and one diagonal is

\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}

Insert the values

\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2

Area with two diagonals length can be given by

\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m

Thus, the area of the rhombus is 864\ m^2 and the length of the other diagonal is 24\ m

4 0
3 years ago
The perimeter of a rectangle is 40 inches. If the length is four less than twice the width, find the dimensions and area
Vinvika [58]

Answer:

<u>L = 12 inches and W = 8 inches</u>

<u>Area = 96 in^2</u>

Step-by-step explanation:

Perimeter(P) = 2(width) + 2(length)

Let W = width and L = length

P = 2W + 2L

L = 2W - 4

Substitute:  P = 2W + 2(2W - 4)

P = 6W - 8

P = 40 inches

40 = 6W - 8

6W = 48

W = 8

L = 2W - 4

L = 2(8) - 4

L = 12

<u>L = 12 inches and W = 8 inches</u>

<u>===============================</u>

Check to see if this works:  

P = 2W + 2L

P = 2(12) + 2(8)

P = 24 + 16

P = 40 inches  <u>YES</u>

<u>========</u>

Area = WxL

Area = (12)*(8)

<u>Area = 96 in^2</u>

7 0
2 years ago
Tap on the photo pls help
DerKrebs [107]

Answer:

49

Step-by-step explanation:

5^2 - 4(-3)(2)

5^2 - 4(-6)

25 - 4(-6)

25 - (-24)

49

Hope this helps!

8 0
3 years ago
Read 2 more answers
g Gravel is being dumped from a conveyor belt at a rate of 40 cubic feet per minute. It forms a pile in the shape of a right cir
Zepler [3.9K]

Answer:

\frac{16}{10\pi} feet per minute.

Explanation:

We have been given that g Gravel is being dumped from a conveyor belt at a rate of 40 cubic feet per minute. It forms a pile in the shape of a right circular cone whose base diameter and height are always equal.

This means that 2 times radius is equal to height that is 2r=h.

Let us solve for radius as:

r=\frac{h}{2}

We will use cone formula to solve our given problem.

V=\frac{\pi r^2 h}{3}

Now, we will rewrite volume function in terms of height as:

V=\frac{(\frac{h}{2})^2 h\pi }{3}

V=\frac{\frac{h^2}{4} h\pi }{3}

V=\frac{h^3\pi }{3\cdot 4}

V=\frac{\pi }{12}\cdot h^3

Now, we will find derivative of volume with respect to time.

V'=\frac{\pi }{12}\cdot 3h^2\cdot h'

V'=\frac{h^2\pi }{4}\cdot h'

Now, we will substitute h=25 and v'=40 and solve for h' as:

40=\frac{(10)^2\pi }{4}\cdot h'

40=\frac{100\pi }{4}\cdot h'

40\cdot \frac{4}{100\pi}=\frac{100\pi }{4}\cdot \frac{4}{100\pi}\cdot h'

\frac{160}{100\pi}= h'

h'=\frac{16}{10\pi}

Therefore, the height of the pile is increasing at a rate of \frac{16}{10\pi} feet per minute.

5 0
4 years ago
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