There are two equations and two variables. You can solve for each variable using either the elimination method or the substitution method. Here, I believe the elimination method would be best:
5a = -4b + 5
3a = -2b + 3
You can multiply the second equation by two, so the 4b and -4b in both equations will cancel each other out when you add them. So:
5a = -4b +5
6a = 4b +6
Add both equations together.
11a = 11
a = 1
Plug in the a value into any of the previous equations:
5(1) = -4b + 5
-4b = 0
b = 0
So, since we know that b = 0, 6b is also 0.
Answer:
SinA=P/H
CosA=B/H
TanA=P/B
Hypotenuse=85
Perpendicular=13
Base=84
SinA=13/85
CosA=84/85
TanA= 13/84
I think it will help you.
What we need to find is how many cookies we can make that have 1/12 cups of candy using 4 cups of candy corn.
What we know:
4 cups of candy
1/12 cup per cookie
We need to divide 4 cups of candy corn into groups of 1/12.
4/(1/12)
4/1 x 12/1=4x12=48
So, we have 48 groups of 1/12 cups of candy corn that means we can make 48 cookies each containing 1/12 cup of candy corn.
Answer:
A
Step-by-step explanation:
dude trust me
Answer:
![a = 1](https://tex.z-dn.net/?f=a%20%3D%201)
Step-by-step explanation:
Given
![4x - 3(x + a) = 2](https://tex.z-dn.net/?f=4x%20-%203%28x%20%2B%20a%29%20%3D%202)
![x = 5](https://tex.z-dn.net/?f=x%20%20%3D%205)
Required
Determine the value of a
![4x - 3(x + a) = 2](https://tex.z-dn.net/?f=4x%20-%203%28x%20%2B%20a%29%20%3D%202)
Substitute 5 for x
![4(5) - 3(5 + a) = 2](https://tex.z-dn.net/?f=4%285%29%20-%203%285%20%2B%20a%29%20%3D%202)
Open all brackets
![20 - 15 - 3a = 2](https://tex.z-dn.net/?f=20%20-%2015%20-%203a%20%3D%202)
![5 - 3a = 2](https://tex.z-dn.net/?f=5%20-%203a%20%3D%202)
Collect Like Terms
![-3a = 2 - 5](https://tex.z-dn.net/?f=-3a%20%3D%202%20-%205)
![-3a = -3](https://tex.z-dn.net/?f=-3a%20%3D%20-3)
Solve for a
![a = -3/-3](https://tex.z-dn.net/?f=a%20%3D%20-3%2F-3)
![a = 1](https://tex.z-dn.net/?f=a%20%3D%201)