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densk [106]
3 years ago
12

Running on a 10-mile loop in the same direction, Sue ran at a constant rate of 8 miles per hour and Rob ran at a constant rate o

f 6 miles per hour. If they began running at the same point on the loop, how many hours later did Sue complete exactly 1 more lap than Rob?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0

Answer:

(C) 5

Step-by-step explanation:

Let x represent number of hours.

We have been given that running on a 10-mile loop in the same direction, Sue ran at a constant rate of 8 miles per hour.

Distance covered by Sue in x hours would be 8x miles.

We are also told that Rob ran at a constant rate of 6 miles per hour, so distance covered by Rob in x hours would be 6x miles.

Since Sue needs to complete one more loop than Rob, so difference of distances covered by Sue and Rob's in x hours should be equal to 10 miles.

We can represent this information in an equation as:

8x-6x=10

2x=10

\frac{2x}{2}=\frac{10}{2}

x=5

Therefore, 5 hours later Sue will complete exactly 1 more lap than Rob and option C is the correct choice.

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Lim x>-1 x^2-x-2/x+1
antiseptic1488 [7]

Answer:

-3

Step-by-step explanation:

If we directly evaluate the function at -1, we get 0/0, meaning we may still have a limit to find.

In this case, factoring the polynomial at the top would be helpful.

The polynomial can be factored to (x+1)(x-2), so the function would now turn out to be (x+1)(x-2)/(x+1)

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Quick disclaimer: the function is still undefined at -1; it's just that the function gets closer and closer to -3 as you approach -1.

I hope this helped you.

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