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Romashka [77]
3 years ago
12

Helppp ASAAPPPP WILL MARK AS BRAINLIST

Mathematics
1 answer:
Talja [164]3 years ago
8 0
<h2>GOOD LUCK ON SOLVING THAT KIDDO! </h2>

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12x&gt;9 (2x-3)-15 solve for x and show steps please.
Verdich [7]

12x > 9(2x-3)-15

distribute the 9

12x > 18x-27 -15

combine like terms on the right side

12x > 18x-42

subtract 18x from both sides

-6x > -42

divide both sides by -6

x = -42 / -6 = 7

x >7

4 0
4 years ago
Read 2 more answers
Determine the y-intercept of the graph.
Georgia [21]

Answer:

Your y intercept is 1.

Step-by-step explanation:

slope is y2-y1 over x2-x1, or 2.

slope intercept formula is y=mx+b, and if you plug values into formula you get 3=2(1)+b

and if you solve that, 2x1=2, 3-2=1.

then you get 1 as your y intercept.

6 0
3 years ago
Answer to this please!
lapo4ka [179]

according to mid point theorem:

Bf=1/2CE

=45

3 0
3 years ago
I just need a little help​
iris [78.8K]

Answer:  

your answer should be 2 and 1/4ths

Step-by-step explanation

2 and 1/4ths bc 5 is more than 4 and there is already a whole so there for there are going to be 2 wholes then there are still parts left over and its out of 4 and there is only one left over so there for it would be 1/4ths.

7 0
3 years ago
Triangle fgh is inscribed in circle o the length of radius oh is 6 and fh is congruent to og. what is the area of the sector for
Vilka [71]
Given :
<span>Triangle fgh is inscribed in circle o
</span>
oh = 6 = radius of the circle 
<span>∵ fh is congruent to og
</span>
<span>∴ fh = og = radius og the circle = 6
</span>
<span>∵ of = radius of the circle = 6
</span>
<span>∴ oh = fh = of = radius of the circle = 6
</span>
∴ Δ foh is Equilateral Triangle

<span> </span>∴∠ foh = 60° ⇒⇒⇒ property of <span>the equilateral Triangle
</span>
∵ total area of the circle = π r²  and total central angle of the circle = 360°
∴ Area of sector foh = (60°/360°) * π r²
∴ Area of sector foh = (60°/360°) * π * 6² ≈ 18.85

The answer is:

<span>the area of the sector formed by angle foh  = 18.85</span>
4 0
3 years ago
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