Answer:

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Step-by-step explanation:
Normal with mean 6.88 minutes and
a standard deviation of 0.57 minutes.
Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)


y ≈ normal (μ, σ)
The z score is the value decreased by the mean divided by the standard deviation

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Answer:
0.15866 is the probability of the average fracture strength of selected 100 pieces of glasses that of exceed 14.3.
Step-by-step explanation:
Given that, the strength of a tempered(x) a glass has average 14.1 and has standard deviation 2.
, 
n=number of selected pieces= 100.
The probability that the average fracture strength of 100 pieces of this glass exceed 14.3 is



= 1 - 0.84134
=0.15866.
Answer:
3
Step-by-step explanation:
3x-3=2x
3x-2x=3
x=3
Answer:
They would be 5,150 feet apart.
Step-by-step explanation:
5,000 + 150 = 5,150