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daser333 [38]
3 years ago
9

I need to find all sides and angles

Mathematics
1 answer:
Amanda [17]3 years ago
6 0
Oops ignore it mate asks else
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Is y= 4.3x - 2 a linear equation?
vredina [299]

Answer:

Yes

Step-by-step explanation:

It is in the form of y = mx + b.

5 0
3 years ago
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PLEASE HELP I NEED HELP 10 POINTS
mestny [16]

Answer:

A kite with a 100 foot-long string is caught in a tree. When the full length of the string is stretched in a straight line to the ground, it touches the ground a distance of 30 feet from the bottom of the tree. Find the measure of the angle between the kite string and the ground.

17°

27°

63°

73°Step-by-step explanation:

8 0
3 years ago
Gimme da answers 6th grade math
Arlecino [84]

Answer: D and B

Step-by-step explanation: They are 4 units apart on the y axis

7 0
3 years ago
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Easy problem for you guys to solve
Zepler [3.9K]

In the ΔIJH, the value of the cosec (I) is 1\frac{9}{56}.

Given ΔIJH the length of the hypotenuse is 65,  the length of the base is 33, and the length of the opposite side is 56.

We have to find the value of the cosec (I).

A function of an arc or angle that is most easily represented in terms of the ratios of pairs of sides of a right-angled triangle, such as the sine, cosine, tangent, cotangent, secant, or cosecant.

We know cosec (I) = hypotenuse / opposite side

Substitute the values

cosec (I) = 65/56

              = 1\frac{9}{56}

Hence the value of cosec (I) is 1\frac{9}{56}.

Learn more about  trigonometric function here: brainly.com/question/24349828

#SPJ10

6 0
2 years ago
Write the equation of the line that passes through the points (1, 4) and (9,-8). Put
Kobotan [32]

Start with the slope formula, shown below.

m = y₂ - y₁ / x₂ - x₁

We take the second y minus the first y over the second x minus the first x.

So we have m = -8 - 4 / 9 - 1 or -12/8.

Notice that -12/8 can be reduced to -3/2.

So the slope of this line is -3/2.

The variable that's used to represent slope is <em>m</em>.

So here, we would say that m = -3/2.

5 0
3 years ago
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