Answer:
In the picture I send above shows the step by step how to get the answers. Cheers!
Easy problem for you guys to solve
1 answer:
In the ΔIJH, the value of the cosec (I) is .
Given ΔIJH the length of the hypotenuse is 65, the length of the base is 33, and the length of the opposite side is 56.
We have to find the value of the cosec (I).
A function of an arc or angle that is most easily represented in terms of the ratios of pairs of sides of a right-angled triangle, such as the sine, cosine, tangent, cotangent, secant, or cosecant.
We know cosec (I) = hypotenuse / opposite side
Substitute the values
cosec (I) = 65/56
=
Hence the value of cosec (I) is .
Learn more about trigonometric function here: brainly.com/question/24349828
#SPJ10
You might be interested in
Answer:
The bounded area is 5 + 5/6 square units. (or 35/6 square units)
Step-by-step explanation:
Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)
Such that f(x) > g(x) in the given interval.
This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).
We want to find the area bounded by:
f(x) = y = x^2 + 1
g(x) = y = x
x = -1
x = 2
To find this area, we need to f(x) - g(x) between x = -1 and x = 2
This is:
We know that:
Then our integral is:
The right side is equal to:
The bounded area is 5 + 5/6 square units.