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3241004551 [841]
2 years ago
10

Easy problem for you guys to solve

Mathematics
1 answer:
Zepler [3.9K]2 years ago
6 0

In the ΔIJH, the value of the cosec (I) is 1\frac{9}{56}.

Given ΔIJH the length of the hypotenuse is 65,  the length of the base is 33, and the length of the opposite side is 56.

We have to find the value of the cosec (I).

A function of an arc or angle that is most easily represented in terms of the ratios of pairs of sides of a right-angled triangle, such as the sine, cosine, tangent, cotangent, secant, or cosecant.

We know cosec (I) = hypotenuse / opposite side

Substitute the values

cosec (I) = 65/56

              = 1\frac{9}{56}

Hence the value of cosec (I) is 1\frac{9}{56}.

Learn more about  trigonometric function here: brainly.com/question/24349828

#SPJ10

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You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then
gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is  d\theta_1  =(14.36p)^o

Step-by-step explanation:

From the question we are told that

    The angle of elevation  is  \theta_1  =  15 ^o =  \frac{\pi}{12}

     The height of the tree is  h

      The distance from the base is  D

h is mathematically represented as

            h  = D tan \theta       Note : this evaluated using SOHCAHTOA i,e

                                               tan\theta  =  \frac{h}{D}

Generally for small angles the series approximation of  tan \theta \  is

          tan \theta  =  \theta  + \frac{\theta ^3 }{3}

So given that \theta =  15 \ which \ is \ small

       h = D (\theta + \frac{\theta^3}{3} )

       dh = D (1 + \theta^2) d\theta

=>        \frac{dh}{h} =  \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta

Now from the question the relative error of height should be at  most

        \pm  p%

=>    \frac{dh}{h} =   \pm p

=>    \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta  = \pm p

=>      d\theta  =  \pm  \frac{\theta +  \frac{\theta^3}{3} }{1+ \theta ^2} *    \ p

 So  for   \theta_1

            d\theta_1  =  \pm  \frac{\theta_1 +  \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} *    \ p

substituting values  

          d [\frac{\pi}{12} ]  =  \pm  \frac{[\frac{\pi}{12} ] +  \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} *    \ p

 =>       d\theta_1  = 0.25 p

Converting to degree

           d\theta_1  = (0.25* 57.29) p

            d\theta_1  =(14.36p)^o

4 0
3 years ago
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Justify each step. <br> 3•(10•12)=3•(12•10)<br> =(3•12)•10<br> =36•10<br> =360
ziro4ka [17]

Answer:

3•(10•12)=3•(12•10) = 360 = True

Step-by-step explanation:

left-hand side Simplify the following:

3×10×12

10×12 = 120:

3×120

3×120 = 360:

Answer: 360

______________________

Right-hand side:

Simplify the following:

3×12×10

Hint: | Multiply 12 and 10 together.

12×10 = 120:

3×120

Hint: | Multiply 3 and 120 together.

3×120 = 360:

Answer: 360

5 0
3 years ago
Need help figuring this one out
Dennis_Churaev [7]

Answer:

4.426020408 × 10∧19

Step-by-step explanation:

First, I found what 540 multiplied by 0.0000000028 was. Next, I took 66921428571428.6 and divided it by the product I got on top.

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Answer:

the ball will be in the air for possibly 2.5 seconds and it max hieght was 10 ft

Step-by-step explanation:

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