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2 years ago

Easy problem for you guys to solve

Mathematics

1 answer:

Zepler [3.9K]2 years ago

6 0

In the ΔIJH, the value of the cosec (I) is $1\frac{9}{56}$ .

Given ΔIJH the length of the hypotenuse is 65, the length of the base is 33, and the length of the opposite side is 56.

We have to find the value of the cosec (I).

A function of an arc or angle that is most easily represented in terms of the ratios of pairs of sides of a right-angled triangle, such as the sine, cosine, tangent, cotangent, secant, or cosecant.

We know cosec (I) = hypotenuse / opposite side

Substitute the values

cosec (I) = 65/56

= $1\frac{9}{56}$

Hence the value of cosec (I) is $1\frac{9}{56}$ .

Learn more about trigonometric function here: brainly.com/question/24349828

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Hello :
<span>the nth term of a geometric sequence is :
Un = Up ×r^(n-p) . r is the common ratio
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