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3241004551 [841]
1 year ago
10

Easy problem for you guys to solve

Mathematics
1 answer:
Zepler [3.9K]1 year ago
6 0

In the ΔIJH, the value of the cosec (I) is 1\frac{9}{56}.

Given ΔIJH the length of the hypotenuse is 65,  the length of the base is 33, and the length of the opposite side is 56.

We have to find the value of the cosec (I).

A function of an arc or angle that is most easily represented in terms of the ratios of pairs of sides of a right-angled triangle, such as the sine, cosine, tangent, cotangent, secant, or cosecant.

We know cosec (I) = hypotenuse / opposite side

Substitute the values

cosec (I) = 65/56

              = 1\frac{9}{56}

Hence the value of cosec (I) is 1\frac{9}{56}.

Learn more about  trigonometric function here: brainly.com/question/24349828

#SPJ10

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The length of a rectangle is x times the square root of 100. The width is one-half y more than three-halves x. Given that the ar
dimulka [17.4K]

Answer:

15x^2+5xy-125=0

Step-by-step explanation:

We are give the following in the question:

Dimensions of rectangle:

Length , l =

l = x\sqrt{100} = 10x

Width of rectangle, w =

w = \dfrac{y}{2} +\dfrac{3x}{2}

Area of rectangle = 125 square cm.

Area of rectangle =

A =l\times w

Putting values, we get,

125 = 10x\times (\dfrac{y}{2}+\dfrac{3x}{2})\\\\125 = 5xy+15x^2\\15x^2+5xy-125=0

is the required equation.

7 0
2 years ago
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Oliga [24]

Answer:

Step-by-step explanation:

5.

point = (x, y)

A = (1\frac{1}{2}, 12)

B = (2\frac{1}{2}, 20)

C = (3, 24)

D = (3\frac{1}{2}, 28)

y/x ratios

\frac{12}{1\frac{1}{2} }

\frac{20}{2\frac{1}{2} }

24/3

\frac{28}{3\frac{1}{2} }

6.

(1 2/3, 3 1/3) = 3 1/3 ÷ 1 2/3 = 2

(1 1/4, 2 1/2) = 2 1/2 ÷ 1 1/4 = 2

(3, 7) = 7 ÷ 3 = 2 1/3

(4 1/2, 9) = 9 ÷ 4 1/2 = 2

The ratio 7/3 (x = 3 and y = 7) is not proportionally related to the others.

The other ratios are equal to each other and are therefore in proportion.

7. yes

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2 years ago
PLZ HELP ASAP SIMILARITY
PIT_PIT [208]
LY = 5.2  ,  TY = 3.9
Δ LTN is a right triangle , ∠T = 90° , TY⊥LN
∴ TY² = LY * YN
∴ 3.9² = 5.2 * YN
∴ YN = 3.9²/5.2 = 2.925

∴ LN = LY + YN = 5.2 + 2.925 = 8.125

Δ LYT is a right triangle , ∠Y = 90°
LT² = LY² + YT² = 5.2² + 3.9² = 42.25
∴ LT = √42.25 = 6.5

Δ NYT is a right triangle , ∠Y = 90°
NT² = NY² + YT² = 2.925² + 3.9² = 23.765
∴ NT = √23.765 = 4.875

The preimeter of the rectangle LINT = 2 * (LT + TN)
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3 years ago
Quadrilateral ABCD is a rhombus with an area of 20 square inches.
Ugo [173]

Answer:

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Find the distance between the two points.
marusya05 [52]

Answer:

Step-by-step explanation:

8 0
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