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Anton [14]
4 years ago
15

Convert each repeating decimal to a simplified fraction. Show your work.

Mathematics
1 answer:
Natalija [7]4 years ago
7 0
Say x = 0.77--
Then 10x = 7.7--
Then 10x - x = 7 => 9x=7 => x=7/9

Say x = 2.3-
10x = 23.3-
10x-x = 9x = 21 => x = 21/9

last one is a bit tougher because it has alternating digits

Say x = 1.013--
100x = 101.313--
100x-x = 99x = 100.3 = x = 1003/990

I multiplied the final fraction with 10 to get integers.
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What is the value of y when x= 2y <br> 4x-3=0.4-2y
masya89 [10]
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8 0
3 years ago
A bag contains pieces of paper with the following numbers on them: 1, 2, 3, 5, 7, 9, 10, 11.
liq [111]

Answer:

See below in bold.

Step-by-step explanation:

There are 2 even and 6 odd numbers in the list.

A.

Prob(Picking an odd number) = number of odd numbers / total of numbers

= 6/8 = 0.75.

Prob(Picking a 10) = 1/8 = 0.125.

Answer = 0.75 * 0.125 = 0.09375

= 0.094 to 3 dec. places.

B.

Prob( Picking and even) = 2/8 = 1/4.

Prob( Picking another even without replacement) = 1/7.

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C.

There are 5 numbers greater than 4.

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7 0
4 years ago
Pls help me factorize.Thanks!
Nat2105 [25]

We can change the sign of the second term, so that the two parenthesis are the same:

6(a-1)b^3+3(1-a)b^2 = 6(a-1)b^3-3(a-1)b^2

Now, both terms have in common a 3, becase the numeric factors are 3 and 6. If we factor the 3, we have

6(a-1)b^3-3(a-1)b^2 = 3(2(a-1)b^3-(a-1)b^2)

The parenthesis (a-1) is also in common, so we can factor it as well:

3(2(a-1)b^3-(a-1)b^2) = 3(a-1)(2b^3-b^2)

Finally, both terms in the parenthesis contain b^2, because it's the power of b with the lowest exponent:

3(a-1)(2b^3-b^2) =3(a-1)b^2(2b-1)

So, the factorization is

3b^2(a-1)(2b-1)

You can swap the order of the four factors (3, b^2, a-1 and 2b-1) as you like: the multiplication is commutative.

5 0
3 years ago
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