You can’t really answer this without showing us the the answer you got from item 6
Step-by-step explanation:
please complete your question
Let's see
In ∆ABE and ∆CBE
- BE=BE(Common side)
- AE=EC[Diagonals of a parallelogram bisect each other]
- <AEB=<BEC[90°]
So by
SAS congruence the triangles are congruent
AB=BC
Fact:-
It's already given AC is perpendicular to BD
- It means diagonals are perpendicular to each other
According to general property of rhombus this parallelogram is also a rhombus.
So sides are equal hence AB =BC
Answer:
52 62 72 82 92 102 112 120 121 122 123 124 125 126 127 128 129 132 142
there are 19.
Step-by-step explanation:
For any polynomial equation, The Fundamental Theorem of Algebra tells you that the highest degree present will tell you how many complex roots the equation has. There are only two terms, "
" and "3". The term has a degree of 5, its exponent. The 3 term has a degree of zero, because you could write it as 
using the zero exponent rule.
The degrees present are 5 and 0. Choose the highest one, 5. So, the answer here is D.
