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musickatia [10]
2 years ago
10

1-37.

Mathematics
1 answer:
andre [41]2 years ago
8 0

Answer:

a. 33 sq.m

b.33x sq.m

Step-by-step explanation:

In a) formula of area of rectangle is:

Area= length * width

where 3m is width and 11m is length

Now area = 3 *11

area= 33 sq.m

In b) formula is same as above

area= 3x * 11

area= 33x sq.m

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Arman, Babken, and Cecilia decided to compete in a 100m run. When Arman crossed the finish line, Babken was 10m behind him. When
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200 people were asked to name their favourite sport.
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3 years ago
Express 0.484848..... in p/q form​
cupoosta [38]
<h3>Answer:  16/33</h3>

It's in p/q form where p = 16 and q = 33.

=======================================================

Work Shown:

x = 0.484848.....

100x = 48.4848.....

I multiplied both sides by 100 to move the decimal over 2 spots. Both decimal values for x and 100x have an infinite string of "48"s repeated after the decimal point. When we subtract, those infinite strings will cancel out

100x - x = 99x

48.4848..... - 0.484848..... = 48

So after subtracting straight down, we have the new equation 99x = 48 which solves to x = 48/99

Divide both parts by the GCF 3 to fully reduce

48/3 = 16

99/3 = 33

Therefore, x = 48/99 = 16/33 = 0.484848...

I recommend using a calculator to confirm that 16/33 = 0.484848...

Side note: your calculator may round the last digit, but this is of course rounding error

7 0
2 years ago
A group of high school athletes has an average GPA of 2.7 with a standard deviation of 0.9. a)Find the percentage of athletes wh
mart [117]

Answer:

a) The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is 3.645.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2.7, \sigma = 0.9

a)Find the percentage of athletes whose GPA more than 1.665.

This is 1 subtracted by the pvalue of Z when X = 1.665. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.665 - 2.7}{0.9}

Z = -1.15

Z = -1.15 has a pvalue of 0.1251

1 - 0.1251 = 0.8749

The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.

His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.

Z = \frac{X - \mu}{\sigma}

1.05 = \frac{X - 2.7}{0.9}

X - 2.7 = 1.05*0.9

X = 3.645

John's GPA is 3.645.

8 0
3 years ago
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