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den301095 [7]
3 years ago
12

What is the length of the segment whose endpoints are A(-4, 3) and B (10, 6)?

Mathematics
2 answers:
nlexa [21]3 years ago
7 0
Apply Pythagoras:

length = sqrt( (10--4)² + (6-3)² ) = sqrt(205)
Alik [6]3 years ago
5 0

Answer:  The correct option is (B) \sqrt{205}.

Step-by-step explanation:  We are given to find the length of the segment whose endpoints are A(-4, 3) and B (10, 6).

We know that

the length of a line segment with endpoints (a, b) and (c, d) is calculated using distance formula as follows :

D=\sqrt{(c-a)^2+(d-b)^2}.

Therefore, using distance formula, the distance between the endpoints A(-4, 3) and B (10, 6) is given by

AB\\\\=\sqrt{(10-(-4))^2+(6-3)^2}\\\\=\sqrt{(10+4)^2+3^2}\\\\=\sqrt{14^2+9}\\\\=\sqrt{196+9}\\\\=\sqrt{205}.

Thus, the length of the line segment AB is \sqrt{205}~\textup{units}.

Option (B) is CORRECT.

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Find f(-2) for f(x) = 2(4)^x<br><br> O A.1/16<br> O B.1/8<br> O C. -16<br> OD. - 32
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Answer:

B. 1/8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle f(x) = 2(4)^x\\f(-2) \ is \ x = -2<u />

<u />

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    \displaystyle f(-2) = 2(4)^{-2}
  2. Exponents:                          \displaystyle f(-2) = 2(\frac{1}{16})
  3. Multiply:                               \displaystyle f(-2) = \frac{1}{8}
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Step-by-step explanation:

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The question asks for how much more water in gallons you can save, so do 6.36399999×10^13 - 95555555460 to get 6.35444444×10^13 gallons

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