We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:
Where 
represents the number of objects/people in the set and 
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set
Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get
Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
The answer is 81. You just have to do the division in the traditional way.
Answer:
= 0.38 m/s
Step-by-step explanation:
▪Total distance = 800 m
5 min = 100 m
▪Remaining distance = 800 - 100 = 700 m
20 min = 700 m
▪Total time taken = 20 + 10 + 5 = 35 min
If 1 min = 60 sec
What about 35 min = ?
= 35 x 60
= 2100 sec
▪Average speed = TD ÷ TT
= 800 ÷ 2100
= 0.38 m/s
<h2><u>Answer</u><u> </u><u>:</u></h2>
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<h2><u>To </u><u>find </u><u>:</u></h2>
- Total number of Floors in dool house
<u>➜</u><u> </u><u>Therefore</u><u> </u><u>,</u><u> </u><u>Total</u><u> </u><u>number</u><u> </u><u>of </u><u>floors</u><u> </u><u>can </u><u>be </u><u>find </u><u>out</u><u> </u><u>by </u><u>dividing</u><u> </u><u>the </u><u>total</u><u> </u><u>height</u><u> </u><u>of </u><u>dollhouse</u><u> </u><u>by </u><u>the </u><u>length</u><u> </u><u>of </u><u>one </u><u>floor</u>
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