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emmainna [20.7K]
4 years ago
14

The Chesapeake Bay tides vary between 4 feet and 6 feet. The tide is at its lowest point when time (t) is 0 and completes a full

cycle in 12 hours. What is the amplitude, period, and midline of a function that would model this periodic phenomenon?
Mathematics
1 answer:
Keith_Richards [23]4 years ago
3 0

Step-by-step explanation:

The midline is the average of the lowest point and the highest point.

y = (4 + 6) / 2

y = 5

The amplitude is the distance from the midline to the lowest/highest point:

a = 5 − 4 = 1, or a = 6 − 5 = 1

It's also half the distance between the lowest point and the highest point:

a = (6 − 4) / 2

a = 1

The period is the time it takes to complete a full cycle, so the period is 12 hours.

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Which of the following is an equation of the line that passes through the point (−2, 3) and is perpendicular to the graph of the
Ludmilka [50]

The equation of the line is y=-\frac{1}{3}+\frac{7}{3}

Explanation:

The given equation is y=3 x-2

<u>Slope:</u>

Since, the equation of the line is perpendicular to the equation y=3 x-2, then, the slope is given by

m=-\frac{1}{3}

Hence, the slope is m=-\frac{1}{3}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the point (-2,3) and the slope m=-\frac{1}{3}, in the above formula, we get,

y-3=-\frac{1}{3}(x+2)

Simplifying, we get,

y-3=-\frac{1}{3}x-\frac{2}{3}

     y=-\frac{1}{3}x-\frac{2}{3}+3

     y=-\frac{1}{3}+\frac{7}{3}

Therefore, the equation of the line is y=-\frac{1}{3}+\frac{7}{3}

8 0
4 years ago
Find the ratio of the 16 hours to 1 day<br>​
VARVARA [1.3K]

Answer:

24 hrs= 1day

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3 years ago
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