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2 years ago

HELME PLEASE I WILL MARK THE BRAINEST

Mathematics

1 answer:

Lina20 [59]2 years ago

5 0

Answer:C

Step-by-step explanation:i would say C because its not a negative and it dosent go up 2 let me know if im wrong

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State of the given functions are inverses. Part 3. NO LINKS!!!!

Effectus [21]

Answer:

h(x)=-x-1

let y =-x-1

interchanging role of x & y

x=-y-1

y=-x-1

h-¹(x)=-x-1

again

f(x)=(2-3x)/2

let

y=(2-3x)/2

interchanging role of x & y

x=(2-3y)/2

2x-2=-3y

y=(2-2x)/3

f-¹(x)=(2-2x)/3

Given function are not inverse of each other.

10.

f(x)=-x+3

let y=-x+3

interchanging role of x & y

x=-y+3

y=3-x

f-¹(x)=-x+3

equal to g(x)=-x+3

Given function are inverse of each other.

8 0

2 years ago

Read 2 more answers

A cylinder with a radius of 4 yd and a volume of 80yd (find the height)

Afina-wow [57]

Answer:

Height of the cylinder = 1.60yd

Step-by-step explanation:

Volume of a cylinder =

V = πr^2h

V - volume of cylinder

π - 3.142

r - radius of cylinder

h - height of cylinder

We are provided with

V - 80

r - 4

π - 3.142

h - ?

80 = 3.142 * 4^2 * h

80 = 50.272 * h

To find h, divide both sides by 50.272

80/50.272 = 50.272h/ 50.272

1.599 = h

h = 1.60yd

7 0

3 years ago

Read 2 more answers

a metal alloy weighing 3 mg and containing 40% copper is melted and mixed with 2 mg of pure copper. what percent of the resultin

Oduvanchick [21]

64%, because 40% of 60% is 24%, and 2 mg of pure copper is 40% of the overall alloy, so add 24 and 40

4 0

3 years ago

Emily and Miranda are standing outside. Emily is 5 feet tall and casts a shadow of 28 inches. Miranda's shadow is 29.4 inches lo

trasher [3.6K]

The answer is B. 5 1/4 feet.

4 0

3 years ago

A football player kicks a ball with an initial upward velocity of 47 ft./s. The initial height of the ball is 3 feet. The functi

Rashid [163]

Answer: 3 seconds

We are given the following function:

$h(t)=-16{t}^{2}+V.t+h(o)$ (1)

Where:

$t$ is the time the ball is in the air

$V=47ft/s$ the initial upward velocity

$h(o)=3ft$ the initial height of the ball

$h(t)$ is the final height of the ball. If no one catches it, this will be zero

So, equation (1) changes to:

$-16{t}^{2}+V.t+h(o)=0$ (2)

Substituting the known values:

$-16{t}^{2}+(47ft/s).t+3ft=0$ (3)

This is a quadratic equation in the form $a{t}^{2}+b.t+c=0$ . In order to find $t$ we can use the quadratic formula for the roots:

$t=\frac{-b\pm\sqrt{-4ac}}{2a}$ (4)

Where $a=-16$ , $b=47$ and $c=3$

Substituting this values in (4):

$t=\frac{-47\pm\sqrt{-4(-16)(3)}}{2(-16)}$ (5)

$t=\frac{-47\pm\sqrt{2401}}{-32}$ (6)

$t=\frac{-47\pm\49}{-32}$ (7)

For $t1$ :

$t1=\frac{-47+49}{-32}=-0.0625 s$ (8)>>>> This result does not work for us because is negative

For $t2$ :

$t2=\frac{-47-49}{-32}=3 s$ (9)>>>This is the result

Therefore:

<h2> If no one catches the ball, it will be 3 s in the air</h2>

6 0

3 years ago