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Grace [21]
4 years ago
8

A rectangle has a perimeter of 204 feet. It's length is six feet longer than twice it's width. If L stands for the length of the

rectangle and W stands for its width, write a system of equations that models the information given in this problem and solve it to find the length and width of this rectangle
Mathematics
1 answer:
Ratling [72]4 years ago
7 0

Answer:

L = 70

W = 32

Step-by-step explanation:

P = 2L + 2W

P 204 feet

W = x

L  = 2x + 6

P = 2L + 2W

P = 2*(2x + 6) + 2*x

P = 4x + 12 + 2x

P = 6x + 12

But we know that P = 204  So 6x + 12 = 204

6x + 12 = 204                    Subtract 12 from both sides

6x + 12 - 12 = 204 - 12       Collect like terms on the right

6x = 192                             Divide by 6

x = 192/6

x = 32

Answer

W = 32

L = 2*W + 6

L = 2*32 + 6

L = 64 + 6

L = 70


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y = 8 and x = 3 is more likely to be understood as a ratio. So for the rest of the answer, their relationship would be represented as y:x

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The problem would be finding y when x = 45

Let us proceed on using the previous equation and substitute x with 45 which would look like this:

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Ratios can also be expressed as fractions which would make things more understandable and easy to solve. So the new form of our equation would be like this:

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Another way of looking at the problem, especially problems like these, is to take the whole question or statement as an equation. it would probably look like this:

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