There are 28 ways in which a couple can choose the name of the baby for its name.
<h3>What is defined as the combination?</h3>
- A combination is an algebraic technique for determining the number of possible arrangements in a set of items in which the order of the selection is irrelevant.
- You can choose the items in just about any order in combinations. Permutations and combinations are often confused.
If we need to choose objects from two groups of x and n objects so that one object from each group is chosen, we can do so by calculating the combinations possible by:
= ˣC₁ × ⁿC₁
Let 'x' be the set of first name = 7
Let 'n' be the set of second name = 4
Putting the values in formula;
= ⁷C₁ × ⁴C₁
= 7 × 4
= 28
Thus, there are 28 ways in which a couple can choose the name of the baby for its name.
To know more about the combination, here
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The complete question is-
A couple has narrowed down the choices of a name for their new baby to 7 first names and 4 second names.
How many different first- and second-name arrangements are possible?
9514 1404 393
Answer:
k = -1
Step-by-step explanation:
Put the given value of x in the equation, and solve the resulting equation for k.
2(5 -3) +k(1 +2·5) = k - 5 - 1
2(2) +k(11) = k -6 . . . . simplify a bit
10k = -10 . . . . . . . . . . add -4-k to both sides
k = -1 . . . . . . . . . . . . . divide by 10
The value of k is -1.
_____
<em>Check</em>
Use k = -1 in the original equation and solve for x.
2(x -3) -(1 +2x) = -1 -x -1
2x -6 -1 -2x = -x -2 . . . . eliminate parentheses
x = 7 -2 = 5 . . . . . . add x+7; answer checks OK
Yyyyyyyyyyyyyyyyyyyyyyyyaaaaa
An isosceles triangle has two congruent sides and angles
The value of x in the isosceles triangle is
<h3>How to determine the value of x</h3>
To calculate the value of x, we make use of the following Pythagoras theorem
![x = \sqrt{4^2 + (6/2)^2](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B4%5E2%20%2B%20%286%2F2%29%5E2)
So, we have:
![x = \sqrt{4^2 + 3^2](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B4%5E2%20%2B%203%5E2)
Evaluate the squares
![x = \sqrt{16 + 9](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B16%20%2B%209)
![x = \sqrt{25](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B25)
Evaluate the exponent
![x = 5](https://tex.z-dn.net/?f=x%20%3D%205)
Hence, the value of x is 5
Read more about isosceles triangles at:
brainly.com/question/1475130