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Cloud [144]
3 years ago
8

Can someone tell me the right answer pls and thank you

Mathematics
1 answer:
umka2103 [35]3 years ago
7 0
B. -2 is the aswers

hope it help... :)
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You're making deliveries and can travel 484 miles on 22 gallons of gas. How far can
baherus [9]
836, because 484 divided by 22 is 22, so each gallon can do 22 miles. 38 times 22 is 836.
3 0
3 years ago
Civil engineer wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. He ass
pychu [463]
N(s)= \frac{89s}{14+14( \frac{s}{17})^2 }
\\
\\N'(s)= (\frac{89s}{14+14( \frac{s}{17})^2 } )'= \frac{89\times 14(1+( \frac{s}{17})^2)-89s\times  \frac{28}{17} }{14^2(1+( \frac{s}{17})^2)} 
\\
\\N'(s)=0
\\
\\89\times 14(1+( \frac{s}{17})^2)-89s\times  \frac{28}{17}=0
\\
\\1+( \frac{s}{17})^2- \frac{2s}{17} =0
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\\289+s^2-34s=0
\\
\\s^2-34s+289=0
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\\(s-17)^2=0
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\\s=17

5 0
2 years ago
(a) has no solutions.<br><br>(b) has infinitely many solutions.<br><br>(c) has exactly one solution.
grandymaker [24]

Answer and Step-by-step explanation:

Given

ax + by = c

qx + ry = s

(a) the equation has no solutions if a/q = b/r ≠ c/s, when this happens, we say the system of equations has no solution. For example

x + y = 3

x + y = 5

Subtracting first equation from the second we have:

0 = 2 which is impossible.

(b) the equations have infinite solutions if a/q = b/r = c/s, for example

x + y = 2

x + y = 2

Subtracting the first equation from the second we have

0 = 0, since this is always true, then it has infinite solutions.

(c) the equations have unique solutions if a/q ≠ b/r, for example

x + y = 2

x – y = 1

Adding the first and second equation we have

2x = 3, we can get x from here and definitely y, so we have just one solution.

6 0
3 years ago
Month 1: 93 in
Elodia [21]

Answer:

9.5 inches per month

Step-by-step explanation:

Given the information about the depth of the pond:

Month 1:     93 in

Month 2:    98 in

Month 3:    112 in

From month 1 to month 3, the average rate of change of the depth of the pond, in inches per month can be calculated using formula

\dfrac{\text{Depth}_3-\text{Depth}_1}{3-1}

Hence, from month 1 to month 3, what is the average rate of change of the depth of the pond, in inches per month is

\dfrac{112-93}{3-1}=\dfrac{19}{2}=9.5\ in/month

4 0
3 years ago
Can someone help me?
Wittaler [7]

Answer:

8 that is your answer

Step-by-step explanation:


5 0
3 years ago
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