Answer:
years worked: 14
at least 10 years: 73%
Step-by-step explanation:
The mean is found by adding the years of service and dividing by the number of employees. The total years of service is 417, so the average is ...
average years worked = 417/30 = 13.9 ≈ 14 . . . years
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The percentage of employees that have worked there at least 10 years is found by counting the number with 10 or more years of service and dividing that count by the total number of employees. The result is then expressed as a percentage.
(10 years or over)/(total number) = 22/30 = 0.73_3 (a repeating decimal) ≈ 73%
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Comment on the working
A spreadsheet can be helpful for this. It has a function that can calculate the mean for you. Sorting the years of service into order can make it trivially easy to count the number that are 10 or more, or you can write a function that will do the count for you. (Also, less than 10 means the years are a single digit. There are 8 single-digit numbers in your list.) The hard part is copying 30 numbers without error.
Answer:
The discriminant b2−4ac < 0, the equation has no real number solutions, it has complex solutions
Step-by-step explanation:
9x² - 4x + 1 = 0 ax² + bx + c = 0
The discriminant: b² - 4ac = (-4)² - 4*9*1 = 16 - 36 = -20
b2−4ac < 0, the equation has no real number solutions, it has complex solutions
Answer:
x₂ = 7.9156
Step-by-step explanation:
Given the function ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
If f(x) = ln(x)+x-10
f'(x) = 1/x + 1
f(9) = ln9+9-10
f(9) = ln9- 1
f(9) = 2.1972 - 1
f(9) = 1.1972
f'(9) = 1/9 + 1
f'(9) = 10/9
f'(9) = 1.1111
x₁ = x₀ - f(x₀)/f'(x₀)
x₁ = 9 - 1.1972/1.1111
x₁ = 9 - 1.0775
x₁ = 7.9225
x₂ = x₁ - f(x₁)/f'(x₁)
x₂ = 7.9225 - f(7.9225)/f'(7.9225)
f(7.9225) = ln7.9225 + 7.9225 -10
f(7.9225) = 2.0697 + 7.9225 -10
f(7.9225) = 0.0078
f'(7.9225) = 1/7.9225 + 1
f'(7.9225) = 0.1262+1
f'(7.9225) = 1.1262
x₂ = 7.9225 - 0.0078/1.1262
x₂ = 7.9225 - 0.006926
x₂ = 7.9156
<em>Hence the approximate value of x₂ is 7.9156</em>
Answer: Hope this helps.
13, 7
Step-by-step explanation:
Number one is 13
Number two is 7
Well 7 x 2 = 14, 14-1 = 7, and 7+13 = 20 making the answers true.
I figured out this number by eliminating numbers, I started with 5, ended with 8 to make a range of the possible numbers. Since 5 was too low and 8 was too high I knew the number had to be either 6 or 7, so I did 7 and I got the answer.
3,5,7 are prime factors of 105
