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Helga [31]
3 years ago
5

Define the following

Biology
1 answer:
asambeis [7]3 years ago
6 0

Explanation:

A. Shine-Dalgarno Sequence:

  • This is a binding site found in the messenger RNA (mRNA) in prokaryotic organisms. It is found upstream of the start codon AUG and aids in the initiation of  protein synthesis

B. SRP:

  • Signal Recognition Protein (SRP). This acts by binding to the bacterial ribosome, which as a result restricts protein synthesis.

C. NLS:

  • Nuclear Localisation Signal is a short amino acid sequence, which is responsible for transporting proteins from the cell cytoplasm into the nucleus. The NLS is also responsible for the development of the nuclear envelope of the cell.

D. Ubiquitin:

  • Found predominately in Eukaryota, the ubiquitin is a protein that aids in the control of other proteins within the organism.

E. Specificity Factor:

  • Also known as the sigma factor, is responsible for the initiation of bacterial transcription. It is recycled during the transcription process and is only required at the initiation of transcription.

F. CRP:

  • cAMP Receptor Protein (CRP) is involved in catabolite (glucose) repression and serves as an inducer in the process.

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How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with
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First we must understand the balanced chemical equation:
Pb(NO3)2 + K2CrO4 ==> PbCr04 + 2KNO3

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1.15L of 2.75M potassium chromate = 1.15x2.75 = 3.1625 moles

The important part here is to see that the number of moles of the reactants are different. We know the number of moles of products will be dependent on the number of moles of reactants, and in this case there is less potassium chromate than there is lead nitrate, so this is the limiting factor as there is a one to one relationship with both reactants. Therefore, the number of moles of potassium nitrate produced is 2 x number of moles of potassium chromate. i.e. 6.325 moles of potassium nitrate is liberated.

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Now we simply times the molar mass by the number of moles to yield the final grams liberated: 6.325 moles  x 101.1 grams/mole = 639.4 grams of potassium nitrate is liberated from this reaction.
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