Answer:
0.25%
Explanation:
20 people start the new population. So there are 20 genes or 40 alleles for the recessive disorder phenylketonuria. 2 out of 40 alleles are recessive for the condition hence frequency of the allele = 2/40 = 0.05
Frequency of the allele does not change when the population increases so it is in Hardy-Weinberg equilibrium. According to it, if q is the frequency of recessive allele, q² = frequency of the recessive condition
Here, q = 0.05 So,
q² = (0.05)² = 0.0025
In percentage, it is 100 * 0.0025 = 0.25%
Hence, incidence of phenylketonuria in the new population is 0.25%
One of the most general forms of discomfort or pain one feels at the time of strenous work out is a burning sensation in the muscles or lungs, which goes away after some time, that is, after stopping the activity. This is a result of an accumulation of lactic acid.
Lactic acid is a by-product of the procedure the body goes through when it requires to generate energy more briskly that it does usually, like when one exercises.
The muscles functioning generally produce energy aerobically, that is, by using oxygen, however, when one push himself or herself at the time of workout and enough oxygen is not accessible, then these muscles start producing energy anaerobically, resulting in production of lactic acid as a by-product and ultimately causing burning sensation.
Answer:
This is due to the event of Speciation that happened for the rodents in Island B but not for the rodents in Island C.
Explanation:
- Due to splitting of the population,
- The sub-population of rodents formed in Island B are B1 and B2.
- The sub-population of rodents formed in Island C are C1 and C2.
- In case of Island B, each of the B1 and B2 sub-populations that got split from each other developed certain mutations that were necessary for them to adapt to the particular diverse environment each of them were exposed to, through the period of 50,000 years. These mutations were so varied that reproductive isolation was generated between them that resulted in each of them to develop into different species.Hence, speciation happens here and B1 and B2 are incapable of inter-breeding.
- In case of Island C, each of the C1 and C2 sub-populations that got split might have got exposed to similar environmental change or no environmental change or the environmental change might have been too small to cause drastic change in each of the sub-populations. As a result of this the two sub-populations might have acquired certain mutations to adapt to the environment each of them were exposed to, through a period of 100,000 years. These mutations might not have been too variable or contrasting to cause reproductive isolation between C1 and C2. Hence, no new speciation happens here and C1 and C2 are capable of inter-breeding.
Penicillin was made to help soldiers
Answer:
1) bay - 0%
cream - 0%
buckskin - 100%
2) cream - 25%
bay - 25%
buckskin - 50%
3) co-dominance
Explanation:
Ok so a run down on Punnett Squares, all you have to do is put the parent's genes on the top and right hand side and combine those two genes in the middle as I did in the picture. Now, co-dominance, this basically means that there is no dominant allele. For example, imagine a white flower (W) and a red flower (R). If these two plants were to breed, you would get a pink flower (WR). This means the red allele and the white allele are both co-dominant. It is basically a combination of both genes that result in a mixed phenotype of the two genes, aka red and white makes pink. This is also how you get an AB blood type.
I hope this helps!
